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I am calculating the time difference between 2 times, I want to print the hour min and sec. Can anyone please tell me how to do it.
SELECT CONVERT(VARCHAR(8), DATEADD(ms, DATEDIFF(ms, CONVERT(VARCHAR(8), GETDATE(), 114), CONVERT(VARCHAR(8), VCTime, 114)), 0), 114) AS TImeDifference FROM Test
TimeDifference --------------- 10:51:37 20:51:37 21:51:37 22:21:37 08:51:37 00:51:37
TimeDifference --------------- 10h:51m:37s 20h:51m:37s 21h:51m:37s 22h:21m:37s 08h:51m:37s 00h:51m:37s
One way is to use sub query and concatenation operator
DATEPART function as below:
SELECT ( CAST(DATEPART(HOUR,(TImeDifference)) AS VARCHAR) + 'h:' + CAST(DATEPART(MINUTE,(TImeDifference)) AS VARCHAR) + 'm:' + CAST(DATEPART(SECOND,(TImeDifference)) AS VARCHAR) + 's') FROM( SELECT CONVERT(varchar(8), DATEADD(ms, DATEDIFF(ms, convert(varchar(8),getdate(),114), convert(varchar(8),VCTime,114)), 0), 114) as TImeDifference FROM test ) t
Yes I realized
concat is introduced in
2012 so we can use
Calculate Duration in Days Hours Minutes and Seconds , In Power Query, there is an easy way to use Duration and get the You have the duration in Minutes and want to calculate Hours/Minutes. SELECT GETDATE() 'Today', DATEPART(hour,GETDATE()) 'Hour Part' SELECT GETDATE() 'Today', DATEPART(hh,GETDATE()) 'Hour Part' RESULT: 3. MINUTE part of the DateTime in Sql Server. We can use DATEPART() function to get the MINUTE part of the DateTime in Sql Server, here we need to specify datepart parameter of the DATEPART function as minute or mi or n.
you can follow below way
DECLARE @x int, @dt1 smalldatetime = '2018-08-17 03:24:16', @dt2 smalldatetime = getdate() SET @x = datediff (s, @dt1, @dt2) SELECT convert(varchar, @x / (60 * 60 * 24)) + ':' + convert(varchar, dateadd(s, @x, convert(datetime2, '0001-01-01')), 108)
this will return 1:05:57:00
select cast(date_diff / 3600 as varchar(4)) + 'h:' + cast((date_diff % 3600) / 60 as varchar(4)) + 'm:' + cast(date_diff % 60 as varchar(4)) + 's' from ( select datediff(second, getdate(), VCTime) date_diff from my_table ) a
Windows Forensic Analysis Toolkit, my $hr=hex(substr($li_time,6,2)); my $min=hex(substr($li_time,8,2)); my my ($yr,$mon,$dow,$dom,$hr,$min,$sec,$ms) = unpack("v8",$date); $hr = "0". As such, you would first need to reduce the value to the 32-bit time format, and then to convert local time to UTC (86,400 seconds/hour times the “ActiveTimeBias” We can use the extract() functionality to get the hour and minutes. Note that this requires converting dates to a timestamp datatype (or using systimestamp in your example). Once you have the hours and minutes you can do arithmetic on them and format them to fit your needs. For instance: will display 13.50.
First, you should not be converting to strings to get the difference. I think this should be fine:
SELECT CONVERT(VARCHAR(8), DATEDIFF(ms, CAST(GETDATE() as TIME), CAST(VCTime as TIME)), 114 ) as TImeDifference FROM Test;
Then you want to add "h", "m", and "s". You can use the STUFF() function. But let me do this using
APPLY so the code doesn't look quite so messy:
SELECT ( STUFF(STUFF(TimeDifference_str, 6, 0, 'm'), 3, 0, 'h') + 's' ) as TimeDifference_hms FROM test t CROSS APPLY (VALUES (CONVERT(VARCHAR(8), DATEDIFF(ms, CAST(GETDATE() as TIME), CAST(VCTime as TIME)), 114 ) ) ) v(TimeDifference_str)
wanted to get interval time in the format of Hour:Minute:Seconds , Now firstly I would require total cycle time in the format of "Hour:Minute:Seconds" for each task and. I tried to write a query with Hour(4) to Power Query Formulas. You can also add separate columns for days, hours, minutes and seconds by using simple formulas. The Duration function allows you to get individual component from the #duration. For example, you can get hours from the duration using this formula: =Duration.Hours( #duration(0,0,0, [Sec]) ) DAX formula
Datetime operations and durations, A number of hours, minutes, and seconds, expressed as a DECIMAL(6,0) number. To be properly interpreted, the number must have the format hhmmss., where As mentioned in the above post, Duration.ToRecord([EndTime]-[StartTime]) also handles the requirement perfectly in QueryEditor, You will get the difference in Hr, Min, Sec in different columns, you can concatenate Hrs and Mins column to get the desired result.
MySQL: TIME_FORMAT Function, %r, Time in 12 hour AM or PM format (hh:mm:ss AM/PM) The TIME_FORMAT function only formats the hours, minutes, seconds, and microseconds found in a Excel stores TIME values in decimal numbers, but in day unit. The first way to convert a time value to hours, minutes or seconds number is to use the multiplication formula. The second way is using the excel CONVERT function, an excel function to convert from and to various units of measurement. The third way to use the excel HOUR function
MySQL convert timediff output to day, hour, minute, second format?, To understand the MySQL convert timediff output to day, hour, minute, and second format, you need to use CONCAT() from MySQL.Let us create a table. 3 hour)); Query OK, 1 row affected (0.41 sec) mysql> insert into The Decimal number is the Time component, where 0 is Midnight and 1 the other midnight, thus 0.5 is midday. 1 Second, as a whole number, could be converted to 1 second in DateTime by dividing it by 24 (Hours in Day), dividing again by 60 (Minutes in Hour) and then again by 60 (Seconds in minutes).
- Just a side note: You could optimize your current query to
SELECT CONVERT(VARCHAR(10), DATEADD(ss, DATEDIFF(ss, GETDATE(), VCTime), 0), 108) AS TImeDifferenceif you use seconds instead of milliseconds and the according format specifier (108).
- Please stop entertaining, you are getting what you want in different ways or at least in my way but still you are waiting for more answers. Even you are not responding to the answer which you are said to check and response.
- concat function is not in 2008
- Yes, thanks for the quick response on that, I got the chance to update the answer accordingly. Please check the updated answer.
- I am getting the difference in my query I just need to know how to show H and M in my output
- @RedDevil there is no direct method without logically making in hh:mm:ss in datediff
- 'seconds' is not a recognized datediff option.
- The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart.
- Argument data type time is invalid for argument 2 of dateadd function.
- @RedDevil . . . Of course. That should be