Count all records per day in a specific month

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I have a table named 'incidents' in MariaDB with the data below

+-----+----------+---------------------+
| ID  | status   |     created_at      |
+-----+----------+---------------------+
|  1  | open     | 2018-07-03 16:15:24 |
|  2  | open     | 2018-07-03 16:15:24 |
|  3  | open     | 2018-07-05 16:15:24 |
|  4  | open     | 2018-07-08 16:15:24 |
|  5  | closed   | 2018-07-15 16:15:24 |
+-----+----------+---------------------+

I want to count all 'open' status per day in a month with a parameter to choose which month and year to get.

For example my value for month is '07' and year '2018'. It should return:

+-------+------------+
| count |    date    |
+-------+------------+
|   0   | 2018-07-01 |
|   0   | 2018-07-02 |
|   2   | 2018-07-03 |
|   0   | 2018-07-04 |
|   1   | 2018-07-05 |
|   0   | 2018-07-06 |
|   0   | 2018-07-07 |
|   1   | 2018-07-08 |
and so on up to July 31(should also be dynamic depending on month and year)
+-------+------------+

Try below query:

   select thedate,case when status is null then 0 else 1 end as count
     from (Select '2018-07-01' As [TheDate]
         Union All
         Select DateAdd(month, 1, TheDate) From dt Where [TheDate] < '2018-07-31') as dt left join tablename 
    on dt.thedate=tablename.date

mysql - Count all records per day in a specific month, I want to count all 'open' status per day in a month with a parameter to choose which month and year to get. For example my value for month is '07' and year  Roughly translated: "dates greater than or equal to the date in F5 and less than the date in F5 plus one month". This is a convenient way to generate "brackets" for each month based on a single date. When the formula is copied down column G, COUNTIFS generates the correct count for each month.

Use below code to achieve your result set.

Declare Two variables:

var_from_date = Date of First day of the month. var_daydiff = Number of days of month

         WITH RECURSIVE cte_days (months, days, dates, n) AS
        (
          SELECT DATE(DATE_ADD(var_from_date, INTERVAL 0 DAY)) as dates,
                    0 as n
          UNION ALL
          SELECT DATE(DATE_ADD(var_from_date, INTERVAL n+1 DAY)) as dates, 
                    n + 1 as n 
          FROM cte_days WHERE n <= var_daydiff
        )
        SELECT ch.date, IFNULL(COUNT(t.id), 0) as count
        FROM cte_days ch
        LEFT JOIN table t on ch.dates = t.date
        GROUP BY ch.date;

SQL Query for Counting Records per Day, SQL Query for Counting Records per Day of code or general information multiple times, I would write a quick HTML page for my This SQL query will add up the record count per day based on a column called Year | Month | Day | Visits | If you have Kutools for Excel installed, you can apply its utilities to count the number of occurrences per year/month/weekday/day, or year and month, or month and day, etc. Kutools for Excel - Includes more than 300 handy tools for Excel. Full feature free trial 30-day, no credit card required! Get It Now. 1.

below way you can generate date according to your requirement i have given where gen_date between '2018-07-01' and '2018-12-31' you have to use your date condition that place and use case when and aggregate function

    select gen_date as date ,sum(case when status='open' then 1 else 0 end) as Cnt from

    (    select * from 
        (select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
         (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
         (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
         (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
         (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
         (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
        where gen_date between '2018-07-01' and '2018-12-31'
    ) as T1 left join your_table t2 on T1.gen_date= date(t2.created_at)
group by gen_date

Excel formula: Summary count by month with COUNTIFS, To generate a total count per month, we need to supply criteria that will isolate all the issues that appear in each month. Since we have actual dates in column F,  Supposing you are going to count birthdays which are in a specific month of 8, you can enter the formula =SUMPRODUCT(1*(MONTH(B2:B15)=8)) (B2:B15 is the birthday column, and the 8 is the specific month of August) into a blank cell, and then press the Enter key.

How to count the number of occurrences per year/quarter/month , According to counting criteria, please select the specified day, month and day, etc. Rows dialog box, Blank Rows (all cells  To filter dates in a month, we need dates for the first and last days of that specific month. Although the first day of the month is easy to guess, displaying a month like 11/1/2018 is not ideal. Thanks to formatting options of Excel, we can display a date by its full month name.

How to write a query that counts rows by date?, But instead of getting the count of the entire month as a whole, I want to get the output like following way, total count of each day in a month from a single SQL  We Have a Table ' Service Desk List' Whcih has two fields, "Requested Date" and "Resolved Date". How can I calculate how many of each are populated within each month. I am aiming to use this in a Line Graph to show the difference.

Group by command in date field to list number of records in day wise, Displaying number of records against each day by using group by & count command of last ten days; we want to display total records of each day of last ten days. Year- Month : 2015-Apr, 2016-Jan; Month wise ( in all years ): Jan , Feb hi i need to retrive data from table between specific range of date i am geeting the  This SQL query will add up the record count per day based on a column called “Timestamp.” Transact SQL SELECT DATEPART(YEAR, Timestamp) AS 'Year', DATEPART(MONTH, Timestamp) AS 'Month', DATEPART(DAY, Timestamp) AS 'Day', COUNT(*) AS 'Visits' FROM tblVisits GROUP BY DATEPART(DAY, Timestamp), DATEPART(MONTH, Timestamp), DATEPART(YEAR, Timestamp) ORDER BY 'Year', 'Month', 'Day'

Comments
  • Consider handling issues of data display in the presentation layer/application-level code, assuming you have that (e.g. a simple PHP loop acting upon an ordered array).
  • I get an error when I use 'WITH' in MySQL: Unrecognized statement type. (near "WITH" at position 0)
  • btw, there could be more than 1 record per day.
  • which version of mysql are u using, with will work on 8.0 version. if it lower version then you can use temporary table or derived table
  • Im using 10.1, according to mariadb, 'WITH' is introduced in 10.2 -- I have an error using the code above: Table 'db.dt' doesn't exist.