If both (iDisL == cDisL or iDisL == cDisR) and (iDisR == cDisL or iDisR == cDisR) are False, output is not defined. Note that.

About NameError:

it's raised when a local or global name is not found.

input() error - NameError: name '' is not defined, TL;DR. input function in Python 2.7, evaluates whatever your enter, as a Python expression. If you simply want to read strings, then use  Teams. Q&A for Work. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information.

The NameErrorexception occurs when code tries to access a variable that hasn't been assigned yet.

I would suggest you to define default value for cases when iDisL and iDisR are not equal to cDisL and cDisR.

Python Language - NameError: name '???' is not defined, Python Language NameError: name '???' is not defined. Example#. Is raised when you tried to use a variable, method  Stack Overflow Public questions and answers; Teams Private questions and answers for your team; Enterprise Private self-hosted questions and answers for your enterprise; Talent Hire technical talent

Try this to solve your problem:

output = ""

if iDisL == cDisL or iDisL == cDisR:
    output = iDisL

if iDisR == cDisL or iDisR == cDisR:
    output = iDisR

oFile = open("manout.txt", "w")
oFile.write(output)

Or check if output is "" and don't write the file.

2.1: "NameError: name 'is_hungry' is not defined" yet I pass the test , 2.1: "NameError: name 'is_hungry' is not defined" yet I pass the test. My code: # Class definition class Animal(object): """Makes cute animals.""" # For initializing our  NameError: name 'Tree' is not defined That's because the class has not been defined yet at this point. The workaround is using so called Forward Reference, i.e. wrapping a class name in a string, i.e. class Tree: def __init__(self, left: 'Tree', right: 'Tree'): self.left = left self.right = right

Python error "NameError: name 'sr' is not defined", Other names are defined within the program (ex. variables). If Python encounters a name that it doesn't recognize, you'll probably get NameError:  (Feb-04-2017, 04:50 AM) hsunteik Wrote: Nevermind,my mistake,found the problem and fixed it. Some pointer,there are a style issues and none stander way of doing this stuff.

Intro Python Debugging, A NameError means that Python tried to use a variable or function name, such as hello based on a previous definition. If it hasn't been defined at this point, you  Traceback (most recent call last): File "<pyshell#12>", line 1, in <module> plt.figure() NameError: name 'plt' is not defined Does anybody know why? python python-3.x matplotlib

NameError: name 'magnitude_pruner' is not defined · Issue #466 , NameError: name 'magnitude_pruner' is not defined #466 NameError Traceback (most recent call last) in 16 sys.path.append(module_path)  NameError: name 'xx' is not defined Python knows READ MORE. answered Mar 19 in Python by rahul • 320 points • 16,185 views. python; python-programming; python

Comments

• Well, what happens if neither one of your two if statements is executed?
• Variables spring into existence through magic the first time you assign them a value. If you never do that, they don't exist.
• Try adding a print statement in both if statements and let us know which if works.
• You might also have a problem if both conditions are true, depending on what your expected output is in that case (iDisL or iDisR). If you expect exactly one of them to be true, you need to handle the other cases (i.e. neither or both) as errors.