## how to diselected a row in 2Darray on the basis of condition and find sum of other rows

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i wanted to print the sum of 2Darray on the bases of condition. if a row in 2Darray conation -1 integer add the sum of row and exclude -1 integer. else if a row in 2Darray does not conation -1 integer skip that row and don't add in sum

public class Mainclass { public static void main(String[] args) { int[][] places = { { 2, 3, -1 }, { -1, 4, 5 }, { 2, 3, 4 } }; int ch = -1, col; int sum = 0; for (int row = 0; row < places.length; row++) { for (col = 0; col < places[row].length; col++) { if (places[row][col] == ch) // skip the -1 integer in 2D array { } if (ch != places[row]) // here i want to diselected the row that do not conatin -1 // integer // skip row that does not contain -1 { } sum += places[row][col]; // print the sum of row that contain -1 and also exclude -1 // integer in sum } } System.out.println(sum); // and the sum should be 2+3+4+5=14 } }

In case of -1 that can appear only once that will work:

int [][] places = { {2,3,-1}, {-1,4,5}, {2,3,4} }; int sum=0; for(int row=0;row<places.length;row++) { if(Arrays.stream(places[row]).filter(x->x==-1).findAny().isPresent()){ sum+=Arrays.stream(places[row]).sum()+1; } }

output:

14

**Program to find the Sum of each Row and each Column of a Matrix ,** The sum of each row and each column can be calculated by traversing through the matrix and adding up the elements. Below is the implementation of the above 0 how to diselected a row in 2Darray on the basis of condition and find sum of other rows Aug 14 '18 0 Using comparator with multiple comparators Aug 6 '18 0 HashSet internal storing same hash bucket Jul 25 '18

You may compute a temporary sum for each row, that you will only add to the final sum is there was no `-1`

.

See this example with some comments :

public static void main(final String args[]) throws IOException, ParseException { int[][] places = { { 2, 3, -1 }, { -1, 4, 5 }, { 2, 3, 4 } }; int ch = -1, col; int sum = 0; for (int[] place : places) { int tempSum = 0; // sum of the current row only boolean containsMinusOne = false; for (col = 0; col < place.length; col++) { if (place[col] == ch) // skip the -1 integer in 2D array { containsMinusOne = true; continue; // skip the rest of this iteration, -1 won't be added to the temp sum below. } tempSum += place[col]; } // if there was a -1, add the sum of this row if (containsMinusOne) { sum += tempSum; } } System.out.println(sum); }

**Finding the Sum of Rows and Columns in a Two-Dimensional Array ,** This program shows you how to find the sum of rows and columns in a two how to use a Duration: 5:14
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What about just use simple `for...each`

? Seems to me it looks pretty simple and clear:

public static long sum(int[][] places) { long res = 0; for (int[] row : places) { int sum = 0; boolean apply = false; for (int col : row) { if (col != -1) sum += col; else apply = true; } res += apply ? sum : 0; } return res; }

*Example:*

int[][] places = { { 2, 3, -1 }, { -1, 4, 5 }, { 2, 3, 4 } }; System.out.println(sum(places)); // 14

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The solution can be direct, finding row sum and keeping a boolean variable which checks if the row contains -1 or not.

if the value of the boolean variable is true, we add the row sum to the total, else skip it.

int [][] places = { {2,3,-1}, {-1,4,5}, {2,3,-1} }; int ch=-1,col; int sum=0; for(int row=0;row<places.length;row++) { boolean rowCheck = false; int rowSum=0; for( col=0;col<places[row].length;col++) { rowSum+=places[row][col]; // print the sum of row that contain -1 and also exclude -1 integer in sum if(places[row][col]==ch) // skip the -1 integer in 2D array { rowCheck=true; rowSum+=1; } } if(rowCheck) sum+=rowSum; } System.out.println(sum);

**TOPCAT,** There are two basic ways to join tables together: top-to-bottom and side-by-side. These criteria give conditions for whether two items (table rows) count as If you want to calculate aggregating functions like sum, min, max etc on multiple Subset From Unselected Rows: Defines a new Row Subset arrange() In the previous tutorial, you learn how to sort the values with the function sort(). The library dplyr has its sorting function. It works like a charm with the pipeline. The arrange() verb can reorder one or many rows, either ascending (default) or descending.

Here is a Stream api solution which is quite intuitive.

Arrays .stream(places) .filter(row -> Arrays.stream(row).anyMatch(x -> x == ch)) .mapToInt(row -> Arrays.stream(row).filter(x -> x != ch).sum()) .sum()

- Present the matrix into a stream of integer arrays.
- Filter any of the arrays that doesn't contain the special character.
- Filter the special characters in the particular integer array and sum all the other elements, return the sum to the outer stream.
- Sum up all the returned sums.

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##### Comments

- What's wrong with the code? Does it work? Why doesn't it work? How does conation apply here?
- Have a rowTotal. Have a specialCharFound boolean. If specialCharFound add rowTotal to grandTotal.
- Add sysout at various places, and try to see the flow. Else debug and step through if you're using an IDE like Eclipse.
- yes specialCharFound is -1 but i don't know how to to apply the condition and exlcude specialCharFound -1 in sum . how to diselected row in 2Darray
- Nice way but You need to explain your solution not just throw it . (upvote anyway)
- Thank you I hope to add explanations and perhaps a general case, do note is iterate twice over places[row] array so performance way it's not the best solution