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This question already has an answer here. How to delete elements from a list using a list of indexes?.
BTW this will do for you
x = [12, 45, 55, 6, 34, 37, 656, 78, 8, 99, 9, 4]
index_list = [0, 4, 11]
value_list = []
for element in index_list:
value_list.append(x[element])
for element in value_list:
x.remove(element)
print(x)
Delete elements from python array with given index of elements as list, This question already has an answer here. How to delete elements from a list using a list of indexes?. BTW this will do for you x = [12, 45, 55, 6, Given an index, remove the element at that index from the list and print the new list. Examples: Using traversal in the list, append all the index values except the given index to a new list and then print the new list. For this we will require a new list where we can append all the values except the given index value.
You could also use enumerate:
x = [12, 45, 55, 6, 34, 37, 656, 78, 8, 99, 9, 4]
index_list = [0, 4, 11]
new_x = []
for index, element in enumerate(x):
if index not in index_list:
new_x.append(element)
print(new_x)
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You can sort the del_list list in descending order and then use the list.pop() method to delete specified indexes:
for i in sorted(del_list, reverse=True):
x.pop(i)
so that x would become:
[45, 55, 6, 37, 656, 78, 8, 99, 9]
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Comments it is because after deleting 0th and 4th index element total list size is not > 11, that's why it gives index out of range error. Use x = [e for i, e in enumerate(x) if i not in index_list], well known pattern If the question already has an answer, then flag as a duplicate, do not answer.
