regex for a whole word containing dots within a sentence

regex line break
regex any character
regex any number of characters

I am looking for a regular expression to catch a whole word or expression within a sentence that contains dots:

this is an example for what I am looking for

In this case i want to catch ""

I tried with this regex:

  • (.*) some signs or not

  • (\b.+\..++\b) a word containing some signs followed by at least on dot that is followed by some signs and this at least once

  • (.*) some more signs nor not#

but it gets me: "abc.123 for what I am looking for"

I see that I got something completely wrong, can anyone enlighten me?

Try this pattern: (?=\w+\.{1,})[^ ]+.

Details: (?=\w+\.{1,}) - positive lookahead to locate starting of a word with at least one dot (.). Then, start matching from that position, until space with this pattern [^ ]+.


Regex Examples: Matching Whole Lines of Text That Satisfy Certain , Often, you want to match complete lines in a text file rather than just the part of of our original regular expression John, we simply use the dot and the star. matches a complete line of text that contains any of the words “one”, “two” or “​three”. With the help of my colleague,we came out with a simple regex to find the occurrence of exact word in a long string, even if the word is surrounded by comma, full-stop or some other character. The regex is:-

If you need to match part of a string you don't need to match entire string (unless you are restricted by a functionality).

Your regex is so greedy. It also has dots every where (.+ is not a good choice most of the time). It doesn't have a precise point to start and finish either. You only need:


It looks for strings that begin and end with word characters and contain at least a period. See live demo here

Regex Tutorial - \b Word Boundaries, In regular expressions, \b anchors the regex at a word boundary or the a “​whole words only” search using a regular expression in the form of \bword\b. The engine starts with the first token \b at the first character T. Since this token is +\M. Using \w instead of the dot automatically restricts the first \y to the start of a word,  The problem with the second on, is that it it contains 7.5 so the parser ends the previous sentence at 7 and he can’t start the next one because it is a 5 instead of a captivate Letter. This is a tricky one, since a . doesn’t mean a sentence boundary. I don’t know if it can be done, I’ll look into it.

This regex pattern matches strings with two or more dots:


"." matches any character except line-breaks "*" repeats previous tokens 0 or more times "." matches a single dot, slash is used for escape

.* Match any character and continue matching until next token

(.) Match a single dot

test. abc.123

.* Again, any character and continue matching until next token

. Matches a single dot

test.example. com

.* Matches any character and continue matching until next token

Perl, Wild cards are 'dots' placed within the regex along with the required word to be confusion, we can only print the searched words and not the whole sentence. With some variations depending on the engine, regex usually defines a word character as a letter, digit or underscore. A word boundary \b detects a position where one side is such a character, and the other is not. In the everyday world, most people would probably say that in the English language, a word character is a letter.

14 Strings, Turkish has two i's: with and without a dot, and it # has a different rule for In your own words, describe the difference between the sep and collapse To force a regular expression to only match a complete string, anchor it with both ^ and $ : Now we can select the sentences that contain a colour, and then extract the  Regular Expression to . Character classes. any character except newline \w \d \s: word, digit, whitespace

Step-by-step tutorial for using the Regex Dictionary, Note that the syntax for patterns in PHP's regular expressions closely resembles Perl's. A search for the string "dictionary" means "Find any word containing these ten Using nine dots instead of the \w nine times will also return apostrophized Match any word that has at least 4 characters, The entire dictionary with the  1. java regex word boundary matchers. Boundary matchers help to find a particular word, but only if it appears at the beginning or end of a line. They do not match any characters. Instead, they match at certain positions, effectively anchoring the regular expression match at those positions.

Syntax for Regular Expressions, captures any email message that has a subject line beginning with the letters abc matches a literal period, rather than any character (dot character) Note: Regular expressions in Content Compliance policies are case sensitive. [^. For example, use this character to specify a space between words in a phrase: The query works by first splitting the text into sentences, and then splitting the sentences into an array of strings that hold each word. For each of these arrays, the Distinct method removes all duplicate words, and then the query performs an Intersect operation on the word array and the wordsToMatch array.

  • You probably need \w+(?:\.+\w+)+
  • thanks a lot, @revo in this case I accept it as a word
  • @Jefeinfiltrado Then we should call it a sub-string and you shouldn't use word boundaries \b. The easiest way to match such sub-strings would be \S+\.\S*.