Remove words in relation to size and not in other list

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I am trying to delete words that have three letters but that do not belong to a list. I tried to do this:

text = 'je ne suis pas une table'
not_shortword = {'n', 'pas', 'ne'}
remove_shortword = ''.join(shortword for shortword in text if len(shortword) > 4 and shortword not in not_shortword)

My output:

'je e suis pas ue table'

Good output:

ne suis pas table

In addition to missing split() on text, you've got your conditions a little mixed up. Try:

' '.join(
    shortword for shortword in text.split(" ") 
    if len(shortword) >= 3 or shortword in not_shortword
# 'ne suis pas table'

How to remove words from a list in python, The errors you have (besides my other comments) are because you're modifying a list while iterating over it. But you take the length of the list at  Choose the Right Synonym for reduce. decrease, lessen, diminish, reduce, abate, dwindle mean to grow or make less. decrease suggests a progressive decline in size, amount, numbers, or intensity. slowly decreased the amount of pressure lessen suggests a decline in amount rather than in number.

The split() in your case breaks in an array of element by the space (one element of array = one word). Looping through it it the solution

text = 'je ne suis pas une table'
not_shortword = {'n', 'pas', 'ne'}

rep = ' '.join(shortword  for shortword in text.split() if len(shortword ) >= 4 or shortword  in not_shortword)

#returns : "ne suis pas table"

Dropping common terms: stop words, Figure 2.5: A stop list of 25 semantically non-selective words which are content relative to the domain of the documents being indexed, as a stop list , the cost of including stop words is not that big - neither in terms of index size nor in terms​  The replace function lets you replace text based on its location and length. In this case, we want to strip off the drive and path, and leave only the document name. The length of this part of the string (text) is 24 and the starting position is 1, and the pattern never changes.

Make sure you are splitting the text into a list of words with .split():

remove_shortword = ' '.join(word for word in text.split() if len(word) >= 3 and word not in not_shortword)

Then join with a space instead of an empty string.

Remove All Occurrences of a Specific Value from a List, In Java, it's straightforward to remove a specific value from a List call List.​remove(int), which treats its argument as the index, not the value we want to remove. reference copying, even reallocating the backing array several times. However, if we try it with a different input, it provides an incorrect output:. Yep, there sure are a fair few tags you can use to format your text. Many of these tags create similar results, and a few are new in HTML 4, and so you won't see their effect until your browser begins supporting them.

11. Lists, Lists and strings — and other collections that maintain the order of their items If you try to access or assign to an element that does not exist, you get a runtime error: the program changing all the loops; they will work correctly for any size list: We can also remove elements from a list by assigning an empty list to them​:. Word does not place many limitations on page size or orientation. There is a good chance that your printer sets greater limitations on the paper you use than Word does, so before you make any changes to the page size, you should consult your printer documentation. It may save you a lot of frustration in the long run.

How to reduce word count without reducing content, The average length of an English word is just over five letters. A natural tendency would be to go searching for words you don't need. I can't give you a list of other words to delete, though—context will be important. harder to identify are sequences that are missing from the human reference genome. List Methods in Python | Set 1 (in, not in, len (), min (), max ()…) More methods are discussed in this article. 1. del [a : b] :- This method deletes all the elements in range starting from index ‘a’ till ‘b’ mentioned in arguments. 2. pop () :- This method deletes the element at the position mentioned in its arguments.

Java in a Nutshell, In this respect a List is like an array whose size changes as needed to the List interface defines methods to add or remove an element at a particular index and end of the list, and another version inserts the elements at a specified index. The List interface does not define methods that operate on a range of list indexes. SELECT REPLACE(stringColumnName, cityName, '') FROM YourTable. Or if you want to remove 'cityName' string from out put of a column then. SELECT REPLACE(stringColumnName, 'cityName', '') FROM yourTable. EDIT: Since you have given more details now, REPLACE function is not the best method to sort your problem.

  • Why is "je" not in the final output? Don't you want to delete words whose length == 3 and are not in not_shortword list?
  • I messed up, I want to remove words that are less than 3...
  • This code doesn't produce the desired result - the output here is just 'je une'.
  • Returns je une