Python- Count each letter in a list of words

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So I have a list of words `wordList = list().' Right now, I am counting each letter in each of the words throughout the whole list using this code

cnt = Counter()
for words in wordList:
      for letters in words:
          cnt[letters]+=1

However, I want it to count differently. I want the function to find the most common letter out of all the words in the list, but only by counting each letter per word once (ignoring the fact that some words can have multiple copies of the same letter).

For example, if the list contained 'happy, harpy and hasty', the two p's in happy should only be counted once. So the function should return a list of the highest frequency letters (in order) without double counting. In the above case it would be 'h, a, p, y, r, s"

cnt = Counter()
for words in wordList:
      for letters in set(words):
          cnt[letters]+=1

Counting Word Frequencies with Python, Python has an easy way to count frequencies, but it requires the use of a new Now we want to count the frequency of each word in our list. first a particular string in the list, and then a particular character within that string. cnt = Counter() for words in wordList: for letters in words: cnt[letters]+=1 However, I want it to count differently. I want the function to find the most common letter out of all the words in the list, but only by counting each letter per word once (ignoring the fact that some words can have multiple copies of the same letter).

Add a set call:

cnt = Counter()
for word in wordList:
      for letter in set(word):
          cnt[letter]+=1

Python, print ( "Count of all characters in GeeksforGeeks is :\n " frequency of each word in a string in Python · Python - Prefix frequency in string List · Python | Count all  Python | Count occurrences of each word in given text file (Using dictionary) Many times it is required to count the occurrence of each word in a text file. To achieve so, we make use of a dictionary object that stores the word as the key and its count as the corresponding value.

An alternative approach using the iterator combinators in itertools:

import collections
import itertools

cnt = collections.Counter(itertools.chain.from_iterable(itertools.imap(set, wordList)))

Find and count letters from a list or array Python, It could also be adapted for strings, or even words to create a 'find word' program. Category Duration: 4:26 Posted: Sep 26, 2018 # Initializing Dictionary d = {} # Count number of times each word comes up in list of words (in dictionary) for word in word_list: if word not in d: d[word] = 0 d[word] += 1 Next, reverse the key and values so they can be sorted using tuples.

You can eliminate a for with update, which updates count from an iterable (in this case, a string):

from collections import Counter
words = 'happy harpy hasty'.split()
c=Counter()
for word in words:
    c.update(set(word))
print c.most_common()
print [a[0] for a in c.most_common()]

[('a', 3), ('h', 3), ('y', 3), ('p', 2), ('s', 1), ('r', 1), ('t', 1)]
['a', 'h', 'y', 'p', 's', 'r', 't']

Python Count Occurrences of Letters, Words and Numbers in Strings , In this Python tutorial we will go over how to count occurrences of specific Remove all Duration: 5:21 Posted: Apr 5, 2017 One way would be to make a list of lists, with each sub-list in the new list containing a word and a count: list1 = [] #this is your original list of words list2 = [] #this is a new list for word in list1: if word in list2: list2.index(word)[1] += 1 else: list2.append([word,0])

cnt = Counter()
for word in wordList:
    lSet = set(word)
    for letter in lSet:
        cnt[letter] +=1             

Count number of characters in a list or array Python, show you how to code an algorithm which counts the number of characters in an array or Duration: 4:22 Posted: Sep 26, 2018 Python: Count the occurrences of each word in a given sentence. Last update on July 25 2019 06:07:35 (UTC/GMT +8 hours) Write a Python program to count the occurrences of each word in a given sentence.

Is there a way to count letters in a list of words?, Given the above list we can iterate over it and examine each word, then naively iterate over the word and count the target letter. a_count = 0 for  Suppose you have a word here and you want to count how many characters are present in a variable. The for loop below will be able to count that var = 'Python' j = 0 for i in var: j = j + 1 print(j)

Python: Count the occurrences of each word in a given sentence , Previous: Write a Python program to remove the characters which have odd index values of a given string. Next: Write a Python script that takes  Whats the simpliest way to add the list items to a dictionary and count how many times the item appears in the list. So for the list above I would like the output to be: {'apple': 2, 'red': 3, 'pear': 1}

How to count characters in Python, For example, to find the length of a word would be the following: [code]word = "​doppelkupplungsgetriebe" If you want to count occurrences of each character separately, to generate histogram data, What can we do using lists in Python? from collections import Counter from collections import defaultdict import numpy import operator import pandas import perfplot def counter(a): return Counter(a) def count(a): return dict((i, a.count(i)) for i in set(a)) def bincount(a): return numpy.bincount(a) def pandas_value_counts(a): return pandas.Series(a).value_counts() def occur_dict(a): d = {} for i in a: if i in d: d[i] = d[i]+1 else: d[i] = 1 return d def count_unsorted_list_items(items): counts = defaultdict(int) for item in

Comments
  • In your example, y is in 3 words, but p only in 2, so the result should have y before p.
  • You should really use chain.from_iterable, otherwise the *arg expansion will force the imap to be all evaluated at once
  • Thanks, I fixed the typo
  • While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.