Return all results where the purchase made date is within 7 days of the registration date

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I have so far produced the below code to try and pull the relevant data together.

However with the '+ 7' function it is producing the below issue.

Registration date = '2018-01-01'

It is pulling back purchase dates of 2018-04-08, i.e as long as the day of the day is 7 days greater then it is being deemed acceptable. When in reality what I ma looking for is any all purchases within 7 days of the registration date.

Any advice/help would be greatly appreciated.

select *
from purchases b
inner join registrations r
on r.customer_id = b.customer_id
and day(b.purchase_date) between d(r.account_opening_date) and day(r.account_opening_date) + 7
and r.account_opening_date >= '2018-01-01 00:00:00.0'

Use DATE_ADD instead, DAY() will not work well when dates to compare are in different months.

AND b.purchase_date >= r.account_opening_date AND 
    b.purchase_date <= DATE_ADD(r.account_opening_date INTERVAL 7 Day)

State Laws and Published Ordinances, Firearms, Within 5 days of the date of the sale, assignment or 153 transfer, the dealer shall return receipt requested, legible copies of the register forms to the office of the Where a sale, assignment or transfer is made to a purchaser who resides in a No handgun purchase permit or firearms purchaser identification card shall be​  You should see the shipping refund within 7 days of receiving your product refund. In addition, if you accidentally purchase a song or album from our Digital Music Store using Alexa, that purchase is eligible for return and refund if we receive your request within 7 days of the date of purchase. To request a refund, contact customer service.


you can use window function

 select *
 partition by (order by account_opening_date rows 6 preceding)
 from purchases p, registrations r
 where p.customer_id = r.customer_id
 and r.account_opening_date >= '2018-01-01 00:00:00.0'

Federal Register, 8/1/96–7/31/97 83.96 Location Leslie High School Auditorium, 4141 Hull Road, request disclosure of our preliminary results of review within five days of publication of Any hearing, if requested, will be held 44 days after the date of publication, and Customs shall assess, antidumping duties on all appropriate entries. Contain dates within the following week. Year([SalesDate])* 53+DatePart("ww", [SalesDate]) = Year(Date())* 53+DatePart("ww", Date()) + 1 . Returns items with dates during next week. A week in Access starts on Sunday and ends on Saturday. Contain a date within the last 7 days . Between Date() and Date()-6. Returns items with dates during the last 7 days.


You can simply use +:

select *
from purchases b inner join
    registrations r
    on r.customer_id = b.customer_id and
       b.purchase_date >= r.account_opening_date and 
       b.purchase_date < r.account_opening_date + interval 7 day
where r.account_opening_date >= '2018-01-01';

If you want to do this without the time component, then use the date() function:

    on r.customer_id = b.customer_id and
       b.purchase_date >= r.account_opening_date and 
       b.purchase_date <= date(r.account_opening_date) + interval 7 day
where r.account_opening_date >= '2018-01-01'

Whether you use < or <= depends on the exactly interpretation of "within 7 days". This version assumes that you really want 7-8 days.

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It sounds like you need to use DATE_ADD and DATE MySQL functions.

select *
from purchases b
inner join registrations r
on r.customer_id = b.customer_id
and date(b.purchase_date) between date(r.account_opening_date) and date_add(r.account_opening_date interval 7 day)
and r.account_opening_date >= '2018-01-01 00:00:00.0'

Chapter 16 SQL Data Manipulation Language – Database Design , SELECT – to query data in the database; INSERT – to insert data into a table Each publisher has a Books table that lists all of its books. Aggregate functions perform a calculation on a set of values and return a The result is a datetime value equal to the date plus the number of date parts. WHERE jobs.job_id < 7. Count business days since/until date. To return the number of days between two dates excluding Saturdays and Sundays, use the NETWORKDAYS function. To find out how many working days are left until a certain date, supply the TODAY() function in the first argument (start_date) and your date in the second argument (end_date).


Using DATEADD, DATEDIFF and DATEPART T-SQL Functions in , Since these functions are primarily used in date manipulations, let us first it will show us all the results on Friday, because the current day is not over DATEPART function is used to return a part of a given date in a numeric value. 1 followed by Registration Date (@RegistrationDate) in the DATEADD  SELECT * FROM product WHERE pdate >= DATEADD(day, -30, getdate()). but it now give exactly result. Please tell me how to solve this issue in SQL Server. sql-server sql-server-2008 sql-server-2008-r2 sql-server-2012. improve this question. edited Dec 15 '14 at 9:11. 139 gold badges. 1173 silver badges. 1306 bronze badges. asked Dec 15 '14 at 8:18.


If a date is within 7 days of todays date, Add a conditional highlight when this value is "within 7 days" If this is what you are looking for, a small tweak will get rid of that false positive. Scrap that I worked it out, thank you very much all working. Be aware that a blank due date will result in a true value. Make it a Checkbox type column. I have a database that I need to be able to count only the first time a row of data appears. Below is part of the database: Date Customer ID Apt set Confirmed issued sat Result Sale Amount 2/27/2017 5:18:48 PM 397500 1 1 0 0 ROC 2/28/2017 9:03:05 PM 397500 1 1 1 0 1Leg 2


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