Java new File() says FileNotFoundException but file exists

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I have an assignment for my CS class where it says to read a file with several test scores and asks me to sum and average them. While summing and averaging is easy, I am having problems with the file reading. The instructor said to use this syntax

Scanner scores=new Scanner(new File("scores.dat"));

However, this throws a FileNotFoundException, but I have checked over and over again to see if the file exists in the current folder, and after that, I figured that it had to do something with the permissions. I changed the permissions for read and write for everyone, but it still did not work and it still keeps throwing the error. Does anyone have any idea why this may be occurring?

EDIT: It was actually pointing to a directory up, however, I have fixed that problem. file.exists() returns true, however, when I try to put it in the scanner, it throws the filenotfoundexception

Here is all my code

import java.util.Scanner;
import java.io.*;
public class readInt{
        public static void main(String args[]){
                File file=new File("lines.txt");
                System.out.println(file.exists());
                Scanner scan=new Scanner(file);
        }
}

FileNotFoundException when file exists. (Java in General forum at , I have been trying to figure this out for a while but it's not working no matter what I try. File outputFile = new File(path + fileName) ; I also wrote some code for File.exists() and it came back false, so I am drawing a complete blank. I presume you have seen what it says in the remainder of this old thread. However, this throws a FileNotFoundException, but I have checked over and over again to see if the file exists in the current folder, and after that, I figured that it had to do something with the permissions.

The code itself is working correctly. The problem is, that the program working path is pointing to other place than you think.

Use this line and see where the path is:

System.out.println(new File(".").getAbsoluteFile());

Java new File() says FileNotFoundException but file exists , If the file does not exist, the application creates it. However, if the file cannot be created, is a directory, or the file already exists but its permissions are sufficient for changing its content, a FileNotFoundException is thrown. Replace BufferedReader br = new BufferedReader(new FileReader(file.getName())); by BufferedReader br = new BufferedReader(new FileReader(file)); FileNotFoundException is thrown if: If the message of the exception claims that there is no such file or directory, then you must verify that the specified is correct and actually points to a file or directory

Obviously there are a number of possible causes and the previous answers document them well, but here's how I solved this for in one particular case:

A student of mine had this problem and I nearly tore my hair out trying to figure it out. It turned out that the file didn't exist, even though it looked like it did. The problem was that Windows 7 was configured to "Hide file extensions for known file types." This means that if file appears to have the name "data.txt" its actual filename is "data.txt.txt".

Hope this helps others save themselves some hair.

java.io.FileNotFoundException – How to solve File Not Found , A quick and practical guide to FileNotFoundException in Java. I just announced the new Learn Spring course, focused on the A file with the specified pathname does not exist; A file with the specified pathname does exist but is inaccessible for protected void readFailingFile() throws IOException {. Re: java.io.FileNotFoundException but file exists! 807603 Nov 27, 2007 6:44 PM ( in response to 796254 ) Well it's not a matter of blaming but an objectif info: with 1.4 it worked and now with 1.6 no

I recently found interesting case that produces FileNotFoundExeption when file is obviously exists on the disk. In my program I read file path from another text file and create File object:

//String path was read from file
System.out.println(path); //file with exactly same visible path exists on disk
File file = new File(path); 
System.out.println(file.exists());  //false
System.out.println(file.canRead());  //false
FileInputStream fis = new FileInputStream(file);  // FileNotFoundExeption 

The cause of the problem was that the path contained invisible \r\n characters at the end.

The fix in my case was:

File file = new File(path.trim()); 

To generalize a bit, the invisible / non-printing characters could have include space or tab characters, and possibly others, and they could have appeared at the beginning of the path, at the end, or embedded in the path. Trim will work in some cases but not all. There are a couple of things that you can help to spot this kind of problem:

  1. Output the pathname with quote characters around it; e.g.

      System.out.println("Check me! '" + path + "'");
    

    and carefully check the output for spaces and line breaks where they shouldn't be.

  2. Use a Java debugger to carefully examine the pathname string, character by character, looking for characters that shouldn't be there. (Also check for homoglyph characters!)

FileNotFoundException in Java, Let's say /Downloads/supplement2.pdf but I get a FileNotFoundException. I am creating a class -- just a class, no main() and I am receiving the error of in my FileInputStream I get a FileNotFoundException, but I know he file exists, I can  As indicated on Java's API documentation, this exception can be thrown when: A file with the specified pathname does not exist. A file with the specified pathname does exist but is inaccessible for some reason (requested writing for a read-only file, or permissions don't allow accessing the file)

Reading and writing from and to a file can be blocked by your OS depending on the file's permission attributes.

If you are trying to read from the file, then I recommend using File's setReadable method to set it to true, or, this code for instance:

String arbitrary_path = "C:/Users/Username/Blah.txt";
byte[] data_of_file;
File f = new File(arbitrary_path);
f.setReadable(true);
data_of_file = Files.readAllBytes(f);
f.setReadable(false); // do this if you want to prevent un-knowledgeable 
                      //programmers from accessing your file.

If you are trying to write to the file, then I recommend using File's setWritable method to set it to true, or, this code for instance:

String arbitrary_path = "C:/Users/Username/Blah.txt";
byte[] data_of_file = { (byte) 0x00, (byte) 0xFF, (byte) 0xEE };
File f = new File(arbitrary_path);
f.setWritable(true);
Files.write(f, byte_array);
f.setWritable(false); // do this if you want to prevent un-knowledgeable 
                      //programmers from changing your file (for security.)

FileNotFoundException « error « Java I/O Q&A, Java Examples - File Existence - How to check a file exist or not? This example shows how to check a files existence by using file.exists() method of File class. Live Demo. import java.io.File; public class Main { public static void main(String[] args) { File file = new File("C:/java.txt"); FileNotFoundException; import java.io. FileNotFoundException when file exists. I have been trying to figure this out for a while but it's not working no matter what I try. I have an application that takes input from a user, then turn the input into an XML file using Betwixt. Once the file is generated I read it from Digester and process data.

Java Examples - File Existence, getPath()); if (!p.exists()) { throw new FileNotFoundException(p. FileNotFoundException ex = new FileNotFoundException("File to be modified has not getAbsolutePath(), newLine); String details = "A new line has been added to file " +  The short bit here is that we're somewhat lazy about autodetecting file types and we just use the file extension. So if you save reads as a SAM file but name the path "anythingnotendingindotsam.adam" or if you save features as a BED file but name the path "anythingnotendingindotbednarrowpeakgtfgffetc.adam", we'll try to load it as a Parquet file, in which case we expect to see other metadata files around.

Java Code Examples java.io.FileNotFoundException, A close look at the Java FileNotFoundException, with sample code path) { try { // Create new mapper, read value from new file of // passed path, and is thrown when attempting to access a file that doesn't exist, so let's just right in the produced JSON file, but since we don't have a matching setTagline()  File f = new File(filename); f.exists(); will return true because the path is not a URL, but it is a absolute path. With Spring Framework that is exactly what ResourceUtils.getFile(filename) does - where name can be either a URL or the absolute file path.

Java Exception Handling - FileNotFoundException, java.io.FileNotFoundException but file exists! - Java Programming. T Source code: **internalSave**( new javax.xml.transform.stream. not read this XML file as a java.io.File. Put it in WEB-INF/classes and use getResourceAsStream() to read it from the servlet context. It gives me an error saying "URI is not hierarchical. Previous Next In this post, we will see about FileNotFoundException in java. is thrown by constructors of FileInputStream, FileOutputStream, RandomAccessFile when file is not found on specified path. Exception can also be raised when file is inaccessible for some reason.For example: When you do not have proper permissions to read the files. FileNotFoundException is checked exception so you

Comments
  • What is current directory? Try printing new File(".")
  • Print the path of new File("scores.dat") and double-check to see if it exists in the expected directory.
  • @Steinar it is searching in the correct directory, and it is giving the correct absolute path, however, the file is still not found
  • What is the text of the exception?
  • It's almost certain that you're in the wrong directory. Print new File("scores.dat").getAbsolutePath() and make sure the file's really in that location.
  • Your third case includes the other two, and also includes a number of other easily separable cases such as permission problems, network failures, etc., which isn't very enlightening, and doesn't make any kind of a case for there being 'three cases'. Testing File.canRead() is futile when you already have to catch an exception, and wasteful when the system has to test it anyway during the open.
  • "If the test above returns true" - and what if this returns false? :)
  • While this worked for you, there are problems with this approach. 1) You are making your application platform dependent by using Windows-specific pathname syntax. 2) You are assuming that your code is going to be executed with the current directory set to the build directory (or something). That won't work when you ship the code to someone else.
  • If the file you are trying to read is part of your source code base, a better idea is to copy it into your JAR file (or the file tree containing your compiled classes) and use getResourceAsStream to find it via the (runtime) classpath.