Returning the differences between lists of lists

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I have been having difficulty trying to create a method to return the differences between lists of lists. This is basically what I am looking for:

s1r1=[[1,2,3,4,5,6],[2,4,6,8]]
uniq=[1,3,5,8]

I have been trying to use this method

list(set(s1r1[0])-set(s1r1[1]))

but it has only been returning the number '8'. I then tried using this format

list(set(a).symmetric_difference(set(b))

and it is now saying that I have a syntax error on the last line of my script, even if there is nothing present. Does anyone have any insight?


Using ^ operator for symmetric_difference

a=set([1,2,3,4,5,6])
b=set([2,4,6,8])
a^b

Output

{1, 3, 5, 8}

Python, compute list difference, Use set if you don't care about items order or repetition. Use list comprehensions if you do: >>> def diff(first, second): second = set(second) return [item for item in  How to find the set difference between two lists (LINQ) (C#) 07/20/2015; 2 minutes to read +5; In this article. This example shows how to use LINQ to compare two lists of strings and output those lines that are in names1.txt but not in names2.txt.


This will work for any number of lists:

s1r1=[[1,2,3,4,5,6],[2,4,6,8]]

uniq = [[j for j in k if not all(j in i for i in s1r1)] for k in s1r1]

Yields:

[[1, 3, 5], [8]]

And to return it as a single list:

print([j for i in uniq for j in i])

Yields:

[1, 3, 5, 8]

Python, Python code t get difference of two lists. # Using set(). def Diff(li1, li2):. return ( list ( set (li1) - set (li2))). # Driver Code. li1 = [ 10 , 15 , 20 , 25 , 30 , 35 , 40 ]. The image above demonstrates an array formula in cell B11 that extracts values that only exist in List 1 (B3:B7) and not in List 2 (D3:D8). The same formula is used in cell B15, however, with different cell references.


You don't need to cast to list to do a symmetric difference (disregard the In: Out: they're from my iPython terminal)

In [16]: s1r1 = [[1,2,3,4,5,6], [2,4,6,8]]

In [19]: a = set(s1r1[0])

In [20]: b = set(s1r1[1])

In [21]: ans = a.union(b) - a.intersection(b)

In [22]: print ans
set([8, 1, 3, 5])

In [23]: ans = a.symmetric_difference(b)

In [24]: print ans
set([1, 3, 5, 8])

Symmetric difference is just the opposite of an intersection

Difference Between Two Lists using Python Set & Without Set, It will return those elements from list1 which don't exist in the second. Here is the sample Python program to get the difference of two lists. """ Desc: Using set() to  There are various ways in which difference between two lists can be generated. In this article, we will see two most important ways in which this can be done. One by using the set () method, and another by not using it. Check out this Author's contributed articles. If you like GeeksforGeeks and would like to contribute, you can also write an


>>> a = set(s1r1[0])
>>> b = set(s1r1[1])
>>> uniq = a.union(b) - a.intersection(b)
>>> uniq    
{8, 1, 3, 5}

How to get the difference between two list in Python, and return a value based on the arguments passed. This is an interesting situation that often comes up. Namely, sometimes one needs to differentiate data in two different columns. There are so many processes in which Excel compare two lists and return differences. In this article, we will see the ways on how to compare two columns in Excel for differences.


>>> s1r1 = [[1,2,3,4,5,6],[2,4,6,8]]
>>> list(set(s1r1[0]).symmetric_difference(s1r1[1]))
['1', '5', '8', '3']

Alternatively you the ^ operator for symmetric difference.

>>> list (set(s1r1[0]) ^ set(s1r1[1]))
[1, 3, 5, 8]

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How to subtract a value from every number in a list in Python, Use the in keyword to get the difference between two lists​​ Use a for-loop to iterate through the first list. Use the syntax item not in list to check if item is not in the second list. Append item to a new list if it is not in the second list. Use a list comprehension for a more compact implementation. Someone, such as a business analyst, must first create the external list. Once created, an external list has many of the same features as a native list, but there are some differences that you should know about. They are listed in the following sections. For more information, see Find content about external data. In this article


Python program to list the difference between two lists., Our tasks is to display difference between two lists. lists # Using set() def Diff(A, B): print("Difference of two lists ::>") return (list(set(A) - set(B)))  Tuples are fixed size in nature whereas lists are dynamic. In other words, a tuple is immutable whereas a list is mutable. You can't add elements to a tuple. Tuples have no append or extend method. You can't remove elements from a tuple. Tuples have no remove or pop method.