regular expressions: remove whitespace from start and end
regular expression not allow only spaces
regex ignore whitespace at beginning of line
regex single space
I use this but its not working
\s matches any character that is unicode whitespace.
\S matches any character that is not unicode white space.
So, a regex that matches to a string whose first character is a non-space character can be any of the following:
The following pattern will match any character at the start of a string that is not whitespace.
If you are trying to match the whole string if it does not begin with whitespace use this.
The above answers work just fine for single line string but if you want to accept
\r (Carriage Return),
\n (Line Feed) or
\r\n (End Of Line) then you can use the below regex:
[^ ] : First character should not be a space.
(.*|\n|\r|\r\n)*$ : Any character including Carriage Return, Line Feed and End Of Line, any number of times.
I have tried "^^ *$" and it worked for me.
Regular Expression Examples, (␣), the tab (\t), the new line (\n) and the carriage return (\r) (useful in Windows environments), and these special characters match each of their respective whitespaces. How I could make this regular expression? What should the rest of the regular expression match? Your current regular expression will match any string containing at least one character that isn't alphanumeric or an underscore or a hyphen: is that what you intended? – Johnsyweb Dec 11 '11 at 7:58. ^ Start of line/string. [a-zA-Z] Character is
Learn Regular Expressions - Lesson 9: All this , flavor. In all flavors discussed in this tutorial, it includes [ \t\r\n\f]. That is: \s matches a space, a tab, a carriage return, a line feed, or a form feed. If you only care about the space character (and not tabs or other whitespace characters) and only care about everything before the first space and everything after the first space, you can do it without a regular expression like this: str.substr(0,str.indexOf(' ')); // "72" str.substr(str.indexOf(' ')+1); // "tocirah sneab"
regular expression for allowing text and spaces but should not begin , When you first encounter Regular Expressions, they may seem a bit weird, like Negated character set [^xyz] — It matches anything that is not enclosed in the brackets. \s — Match a whitespace character (spaces, tabs etc). Regex tutorial — A quick cheatsheet by examples. does not return after the first match, (for instance it may be the beginning of the string or a space character).
- What are you trying to do?
- What do you mean by not working? Your regex works pretty fine for me.
- @M42 OP's pattern does not match any non-alpha numeric characters and is also needlessly complex. debuggex.com/r/dlsjoQrphPvuV0u8
- May be OP wants to match only letter or digit in first position, that is what his regex means. But who knows?
- It not worked for me but with your solution I have tried "^[^ ](.*|\n|\r|\r\n)*$" and it worked for me. Just inject the symbol ^ at the start and in the last $.