Accessing the index in 'for' loops?

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How do I access the index in a for loop like the following?

ints = [8, 23, 45, 12, 78]
for i in ints:
    print('item #{} = {}'.format(???, i))

I want to get this output:

item #1 = 8
item #2 = 23
item #3 = 45
item #4 = 12
item #5 = 78

When I loop through it using a for loop, how do I access the loop index, from 1 to 5 in this case?

Using an additional state variable, such as an index variable (which you would normally use in languages such as C or PHP), is considered non-pythonic.

The better option is to use the built-in function enumerate(), available in both Python 2 and 3:

for idx, val in enumerate(ints):
    print(idx, val)

Check out PEP 279 for more.

MS Access - Indexing, Using an additional state variable, such as an index variable (which you would normally use in languages such as C or PHP), is considered non-pythonic. In C++, you must provide an index to access a specific element within the array. An index must be a counting type (such as int), as demonstrated here: nScores[11] = 10; This is akin to the way that rental cars are numbered. However, unlike humans, C++ starts with 0 when numbering its arrays. Thus the …

Accessing the index in 'for' loops?, Python | Accessing index and value in list. There are various methods to access the elements of a list, but sometimes we may require to access element along with  The fastest way to access indexes of list within loop in Python 2.7 is to use the range method for small lists and enumerate method for medium and huge size lists. Please see different approaches which can be used to iterate over list and access index value and their performance metrics (which I suppose would be useful for you) in code samples

It's pretty simple to start it from 1 other than 0:

for index, item in enumerate(iterable, start=1):
   print index, item
Note

Important hint, though a little misleading since index will be a tuple (idx, item) here. Good to go.

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for i in range(len(ints)):
   print i, ints[i]

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As is the norm in Python there are several ways to do this. In all examples assume: lst = [1, 2, 3, 4, 5]

1. Using enumerate (considered most idiomatic)
for index, element in enumerate(lst):
    # do the things that need doing here

This is also the safest option in my opinion because the chance of going into infinite recursion has been eliminated. Both the item and its index are held in variables and there is no need to write any further code to access the item.

2. Creating a variable to hold the index (using for)
for index in range(len(lst)):   # or xrange
    # you will have to write extra code to get the element
3. Creating a variable to hold the index (using while)
index = 0
while index < len(lst):
    # you will have to write extra code to get the element
    index += 1  # escape infinite recursion
4. There is always another way

As explained before, there are other ways to do this that have not been explained here and they may even apply more in other situations. e.g using itertools.chain with for. It handles nested loops better than the other examples.

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Array Indexing - MATLAB & Simulink, Modern for loops have lost a feature compared to the old ones: accessing the position of the current element. Here are some ways to get it  Getting a list when you want an element only postpones the inevitable "list index out of range" - and that's what should happen when attempting to get an element from an empty list. For Strings astr[-1:] could be a valid approach since it returns the same type as astr[-1], but I don't think the ':' helps to deal with empty lists (and the

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Comments
  • Note that indexes in python start from 0, so the indexes for your example list are 0 to 4 not 1 to 5
  • As Aaron points out below, use start=1 if you want to get 1-5 instead of 0-4.
  • Does enumerate not incur another overhead?
  • The question was about list indexes; since they start from 0 there is little point in starting from other number since the indexes would be wrong (yes, the OP said it wrong in the question as well). Otherwise, calling the variable that is tuple of index, item just index is very misleading, as you noted. Just use for index, item in enumerate(ints).
  • Better is to enclose index inside parenthesis pairs as (index), it will work on both the Python versions 2 and 3.
  • @AnttiHaapala The reason, I presume, is that the question's expected output starts at index 1 instead 0
  • That should probably be xrange for pre-3.0.
  • Use enumerate instead
  • For Python 2.3 above, use enumerate built-in function since it is more Pythonic.
  • Enumerate is not always better - it depends on the requirements of the application. In my current situation the relationships between the object lengths is meaningful to my application. Although I started out using enumerate, I switched to this approach to avoid having to write logic to select which object to enumerate.
  • @adg I don't see how avoid enumerate saves any logic; you still have to select which object to index with i, no?
  • This is not wrong and is used in C/C++ and others. It's considered as non-pythonic, but can also be used in python. Like simple solutions that break it down to the source :+