for i in range: TypeError: 'type' object is not iterable

object is not iterable django
python json object is not iterable
typeerror: 'collection' object is not iterable
self child to_representation item for item in iterable typeerror int object is not iterable
typeerror type object argument after * must be an iterable, not int
type is not iterable python
django type' object is not iterable
typeerror sseclient object is not iterable

Say you have a list value like this:

spam = ['apples', 'bananas', 'tofu', 'cats']

Write a function that takes a list value as an argument and returns a string with all the items separated by a comma and a space, with 'and' inserted before the last item.

For example, passing the previous spam list to the function would return 'apples, bananas, tofu, and cats', but your function should be able to work with any list value passed to it

My cod is below. When running, it shows TypeError and print(value, sep = ', ') won't work; They are not separated with comma and space.

def command(arg):
    arg.insert(-1, 'and')
    value = arg
    for i in range:
        print(value, sep =', ')


spam = []
while True:
    print('Enter the list values:')
    listvalue = input()
    if listvalue == '':
        break
    spam = spam + [listvalue]
command(spam)

You have to specify the range value with range(stop)or range(start, stop[, step]). Maybe range(len(value)) if value is a list.

You get the exception TypeError: 'type' object is not iterable because you are referencing the class range instead of calling it.

Python: range is not an iterator!, I love this question because range objects in Python 3 (xrange in Python 2) are line 1, in <module> TypeError: 'range' object is not an iterator for i in range(fil): for j in range(col): if A[i][j] > 0: Your code incorrect because it is attempting to call the range object: So the call to range(fil) creates a new range object, and then Python attempts to call that object as though it were a function, passing col to it as an argument.

You need a start and an end point for the FOR loop.

eg. this will return "This is printed" 10 times.

for i in range(0,9):
    print("This is printed")

Python range() built-in-function, Now let us understand the concept of range function() in python, below 3 print(i)TypeError: 'float' object cannot be interpreted as an integer. for i in range(c/10): TypeError: 'float' object cannot be interpreted as an integer

Here is the code which does that

def listfunction(stringList):
    strings = ''
    j=0
    for i in range(len(stringList)):
        j=i
        if j == (len(stringList)-1):
            strings = strings + 'and ' + str(stringList[i]) + '.'
        else:
            strings = strings + str(stringList[i]) + ',' + ' '
        #print(strings)   
    return strings

Could you please help me to resolve this error? Bummer! TypeError , The range function is a great way to loop for a specified number of times. For example: range(5). returns. [0, 1, 2, 3, 4]. So instead of. for num in Dismiss Join GitHub today. GitHub is home to over 40 million developers working together to host and review code, manage projects, and build software together.

TypeError- range() integer end argument expected, got list., TypeError: range() integer end argument expected, got list. TypeErrors occur when you try to use a function or method incorrectly for that type. They usually come TypeError: "x" is read-only; TypeError: 'x' is not iterable; TypeError: More arguments needed; TypeError: Reduce of empty array with no initial value; TypeError: X.prototype.y called on incompatible type; TypeError: can't access dead object; TypeError: can't access property "x" of "y" TypeError: can't assign to property "x" on "y": not an object

Unable to create a list using range function. : learnpython, list(range(1,10)) Traceback (most recent call last): File "<pyshell#134>", line 1, in <module> list(range(1,10)) TypeError: 'list' object is not callable > Python's range() vs xrange() Functions. You may have heard of a function known as xrange(). This is a function that is present in Python 2.x, however it was renamed to range() in Python 3.x, and the original range() function was deprecated in Python 3.x. So what's the difference?

Python range() function, The range() function is used to generate a sequence of numbers. range() is for i in range(3.3): TypeError: 'float' object cannot be interpreted as an integer Contact Information #3940 Sector 23, Gurgaon, Haryana (India) Pin :- 122015. contact@stechies.com

Comments

for i in range ??? range of what ?
for i in range… what range exactly…?
Did anybody say "what range" yet?
actually range has not been defined in your command function
i have to print from index[0] to index[-1]. so it will be for i in range(strating list index) to (last list index) right?
He's not calling the function, that's the problem…
Yes I meant he is calling the object not the function, I should make it more clear.
No, he's trying to iterate a function object (without calling it)…
@Tiphaine he is _still not calling anything. "calling" means "applying the call operator" (which is the parens), which will activate the __call__ method of the object (if it has one of course - else you get a TypeError "object is not callable"). Also, in Python 3, range is a class, not a function.
i have to print from index[0] to index[-1]. so it will be for i in range(strating list index) to (last list index) right?
yes you should be able to do it that way. personallly if you are wanting to do it like that i would create a variable which is equal to the list length and use the variable for the end point in the for loop just so the code can still run with different lengths of lists