How to grep a specific path from output of unzip -l

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I need to extract the path to the Info.plist file right after the .app folder.

$ unzip -l test.ipa | grep Info.plist
258  05-25-2018 11:52   Payload/test.app/CDVLaunchScreen.storyboardc/Info.plist
2197  05-25-2018 11:52   Payload/test.app/Info.plist

The problem is that the .app folder is named different in every .ipa file. I can't grep for Payload/test.app/Info.plist. I've tried:

$ unzip -l test.ipa | grep Payload/*.app/Info.plist
$ unzip -l test.ipa | grep "Payload/..app/Info.plist"

which yields nothing.

How would the correct grep argument look like? Also how would I only extract the path(Payload/test.app/Info.plist) instead of the whole row (2197 05-25-2018 11:52 Payload/test.app/Info.plist)?

unzip -l test.ipa | grep -o 'Payload/.*\.app/Info\.plist'

The regex you need is Payload/.*\.app/Info\.plist. Notice the escaped dots - they have to be matched literally.

.* will be interpreted by shell unless you enclose the grep parameter into quotes (double quotes would also be fine in your case since no variable expansion collision may happen in this particular expression).

Finally, -o switch tells grep output only the match.

Using unzip, grep and cut, This way the output of the cut command is used as input for the unzip. unzip /​mnt/cdrom/$date.zip `grep $date $DIR/files.eng | cut -d/ -f2` > /dev/null done Its purpose here is to remove the file path so the substituted command returns only It's targeting specific, predetermined files to be updated. Hi all, I would like to ask whether in Unix shell/perl have any functions or command to allow grep/cat/read a file inside compressed .tgz without extract it? I know we can tar tvf a compressed tgz but this only allow we read the path/filename contained inside the tarball. If we want to read (3 Replies)

In a pattern . means any character and * means 0 or more times the preceeded character.

Your command should be:

unzip -l test.ipa | grep -o 'Payload/.*\.app/Info\.plist'

How to unzip a file in terminal and spit it out with specific file name?, I know I run sudo unzip file.zip -d /path/to/dir , but is there anyway to specify the output file name? command-line files unzip. I think the perfect solution would have to be more complicated though. With this solution, if a particular folder didn't have any files at the relevant depth or shallower, the path would be filtered out completely by the grep. What you would want is for each path to be truncated to the correct depth, and then not to print any duplicate paths.

In case you aren't certain about whether all paths begin with Payload, try

unzip -l test.ipa | grep -P '(?<=\s)\S*Info.plist'

which matches all non whitespace characters before Info.plist.

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