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I am trying to convert a string that is 8 characters long of hex code into an integer so that I can do int comparison instead of string comparisons over a lot of different values.

I know this is fairly trivial in C++ but I need to do it in Java. The test case I need to satisfy is essentially to Convert "AA0F245C" to int and then back to that string so that I know it is converting right.

I have tried the following:

int decode = Integer.decode("0xAA0F245C");  // NumberFormatException
int decode2 = Integer.decode("AA0F245C"); //NumberFormatException
int parseInt = Integer.parseInt("AA0F245C", 16); //NumberFormatException
int valueOf = Integer.valueOf("AA0F245C", 16); //NumberFormatException

I have also tried doing it two characters at a time and multiplying the results, which the conversion works but the number is not right.

int id = 0;
for (int h = 0; h < hex.length(); h= h+2)
    String sub = hex.subSequence(h, h+2).toString();

if (id == 0)
    id = Integer.valueOf(sub, 16);
    id *= Integer.valueOf(sub, 16);             
//ID = 8445600 which = 80DEA0 if I convert it back. 

I can not use third party libraries just so you know, so this has to be done in Java standard libraries.

Thank you for your help in advance.

It's simply too big for an int (which is 4 bytes and signed).


Long.parseLong("AA0F245C", 16);

Convert hex string (char []) to int?, Have you tried strtol() ? strtol - convert string to a long integer. Example: const char *hexstring = "abcdef0"; int number = (int)strtol(hexstring, NULL, 16);. In case​  stoi () stands for string to integer, it is a standard library function in C++ STL, it is used to convert a given string in various formats (like binary, octal, hex or a simple number in string formatted) into an integer. int stoi (const string& str, [size_t* idx], [int base]); const string& str is an input string.

you may use like that

System.out.println(Integer.decode("0x4d2"))    // output 1234
//and vice versa 
System.out.println(Integer.toHexString(1234); //  output is 4d2);

Best Hex to Decimal Converter Online, how to convert hex to decimal? Example. Here is a Hex String: ddd. Decimal version: 3549. Hex to Decimal Conversion Chart  To convert a hexadecimal string to a number. Use the ToInt32(String, Int32) method to convert the number expressed in base-16 to an integer. The first argument of the ToInt32(String, Int32) method is the string to convert. The second argument describes what base the number is expressed in; hexadecimal is base 16. ' Assign the value 49153 to i.

The maximum value that a Java Integer can handle is 2147483657, or 2^31-1. The hexadecimal number AA0F245C is 2853119068 as a decimal number, and is far too large, so you need to use

Long.parseLong("AA0F245C", 16);

to make it work.

Converting Hex string to Int in C#, the above code. In order to parse a 0x prefixed hex literal you need to use the Convert.ToInt32(string value, int fromBase) method instead:  Obtain the char that corresponds to each value in a hexadecimal string. Convert a hexadecimal string to an int. Convert a hexadecimal string to a float. Convert a byte array to a hexadecimal string. Example. This example outputs the hexadecimal value of each character in a string. First it parses the string to an array of characters.

you can easily do it with parseInt with format parameter.

Integer.parseInt("-FF", 16) ; // returns -255

javadoc Integer

Convert hex string to integer using stoi() function in C++ STL, C++ STL stoi() function: Here, we are going to learn how to convert a given hexadecimal string to an integer using stoi() function. I have a char [] that contains a value such as "0x1800785" but the function I want to give the value to requires an int, how can I convert this to an int? I have searched around but cannot find an answer. Have you tried strtol ()? In case the string representation of the number begins with a 0x prefix, one must should use 0 as base:

This is the right answer:

myPassedColor = "#ffff8c85" int colorInt = Color.parseColor(myPassedColor)

Java Convert Hex to Decimal, Java Hexadecimal to Decimal conversion: Integer.parseInt(). The Integer.parseInt​() method converts string to int with given redix. The signature of parseInt()  Convert hex string to int in Python. I may have it as "0xffff" or just "ffff". To convert a string to an int, pass the string to int along with the base you are converting from. Both strings will suffice for conversion in this way: >>> string_1 = "0xffff" >>> string_2 = "ffff" >>> int(string_1, 16) 65535 >>> int(string_2, 16) 65535 Letting int infer

Convert hex string to int in Python, You can convert hex string into an int in Python by following ways:- You must put '​0x' prefix with hex string, it will specify the base explicitly,  I need to convert an int to hex string. When converting 1400 => 578 using ToString("X") or ToString("X2") but I need it like 0578. Can anyone provide me the IFormatter to ensure that the stri

Convert hex string to int, To convert a hex string to int, you can use function strtol ( or strtoul if you want a unsigned result). Alternatively (because I like and use this  Given a hexadecimal string and we have to convert it into an integer number. Converting from hexadecimal string to integer. Let suppose you have a string "3039" which is a hexadecimal value of integer 12345, but this value is in string format, and you want to its integer (number) value.

How to convert hex string into int in Python?, Hex strings generally have a 0x prefix. If you have this prefix and a valid string, you can use int(string, 0) to get the integer. The 0 is provided to  Hexadecimal number system contains values starting from 0 to 15, a total of 16 numbers. Here is the simple online hex to decimal calculator to convert hexadecimal to integer with ease. Just enter a hex value in the Hex to Integer Converter and submit to know the conversion result within the fractions of seconds.

  • You are multiplying when you should be shifting.
  • 0xAA0F245C = 2853119068 but Integer.MAX_VALUE = 0x7fffffff = 2147483647
  • I know the question has been around for two years. However, java 8 enables another solution. They added the Integer.parseUnsignedInt("value",radix) method which serves your purpose. If the value is greater than Integer.MAX_VALUE it is mapped to a negative number.
  • Awesome thank you! I probably should have known that. But it makes me feel better none of the 4 people I asked prior to posting knew it either :). As a side note, I now have to go figure out why the person wrote the code that I need to compare the ints to has them as ints and not longs... which probably means something else is off. That's besides the point... thank you for the quick answer!!!! Also curse you java for your terrible error message... "It's to big" would have been helpful.
  • When I try with big hex string, I get NumberFormatException: For input string: "AF0005E2A6C630059E4754B8799360F5" ... Solution ?
  • @AnumSheraz you don't want to convert to a long but to a byte array. See for example…
  • An alternative to converting to a byte array for a large number is to use the BigInteger class like this: BigInteger value = new BigInteger(valueString, 16)
  • i like this answer, didn't know there is a generic, typeinsensitive method for this in the Integer class. thanks for the knowledge.
  • off: interesting that a more detailed answer albeit 5 minutes later gets only 1 upvote compared to 14. Although true, this one didn't say magical '4 bytes' and 'signed'
  • the link is broken