How to resolve "django.core.exceptions.ImproperlyConfigured: Application labels aren't unique, duplicates: foo" in Django 1.7?
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On upgrading to Django 1.7 I'm getting the following error message from
$ ./manage.py Traceback (most recent call last): File "./manage.py", line 16, in <module> execute_from_command_line(sys.argv) File "/home/johnc/.virtualenvs/myproj-django1.7/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 427, in execute_from_command_line utility.execute() File "/home/johnc/.virtualenvs/myproj-django1.7/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 391, in execute django.setup() File "/home/johnc/.virtualenvs/myproj-django1.7/local/lib/python2.7/site-packages/django/__init__.py", line 21, in setup apps.populate(settings.INSTALLED_APPS) File "/home/johnc/.virtualenvs/myproj-django1.7/local/lib/python2.7/site-packages/django/apps/registry.py", line 89, in populate "duplicates: %s" % app_config.label) django.core.exceptions.ImproperlyConfigured: Application labels aren't unique, duplicates: foo
What's the problem and how do I resolve it?
The problem is that with the changes to apps in Django 1.7, apps are required to have a unique label.
By default the app label is the package name, so if you've got a package with the same name as one of your app modules (
foo in this case), you'll hit this error.
The solution is to override the default label for your app, and force this config to be loaded by adding it to
# foo/apps.py from django.apps import AppConfig class FooConfig(AppConfig): name = 'full.python.path.to.your.app.foo' label = 'my.foo' # <-- this is the important line - change it to anything other than the default, which is the module name ('foo' in this case)
# foo/__init__.py default_app_config = 'full.python.path.to.your.app.foo.apps.FooConfig'
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I found simple solution for this. In my case following line is added twice under INSTALLED_APPS,
Removed one line fixes the issue for me.
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I had the same error - try this:
in INSTALLED_APPS, if you are including 'foo.apps.FooConfig', then Django already knows to include the foo app in the application, there is therefore no need to also include 'foo'. Having both 'foo' and 'foo.apps.FooConfig' under INSTALLED_APPS could be the source of your problem.
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As therefromhere said this is a new Django 1.7 feature which adds a kind of "app registry" where applications must be determined uniquely (and not only having different python pathes).
name attribute is the python path (unique), but the
label also should be unique. For example if you have an app named 'admin', then you have to define the name (name='python.path') and a label which must be also unique (label='my admin' or as said put the full python path which is always unique).
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Well, i created
auth app, and i've included it in
src.auth (because it's in
src folder) and i got this error, because there is
django.contrib.auth app also. So i renamed it like
authentication and problem solved.
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- Questioner didn't accept his own answer, but it is correct. Once you do this, you place 'full.python.path.to.your.app.foo.apps.FooConfig' into your
INSTALLED_APPSand everything works as expected.
- Just wanted to mention, once you add the label run the migration like this: python manage.py makemigrations my.foo
- Does this work for apps with existing database tables? I get a "dependencies reference nonexistent parent node" error when I make migrations after making these changes.
- @John_Carter What's a
'full.python.path.to.your.app.foo'normally look like? Does it involve
os.path? Is it from the project root?
- From my observation it's better to avoid dots in label name. The problem was with: AUTH_USER_MODEL = 'apps.auth.User' (won't work). Changing the label name and AUTH_USER_MODEL to 'apps_auth.User' solved the problem.
- nice observation... it was a silly mistake .. worked for me :)
- This doesn't really give an answer. The question was what's going wrong with the upgrade, and how to fix it so that the upgrade works. Rolling back to an old version avoids the problem, but doesn't fix it.
- @anaximander - They're trying to help, therefore this is an answer, even if it's a poor one. Downvote it if you don't like it, but don't flag it. See Your Answer is in Another Castle, When an Answer is not an Answer: meta.stackexchange.com/questions/225370/…
- On a question saying "how do I do X in C#?" and someone responded "use Java", that would be considered "not an answer". By the same token, when the question is "how do I fix this issue in version 1.7", I'd argue that "use version 1.6.7" is also not an answer. The answer says "If you want to [go] back to [an] older version". The question is "how do I move up to the newer version". I think that's pretty self-evident.
- @anaximander Thank you for your comment. I agree with you. The content as my 'answer' is so short without other reason why I return the older version. I just write the information as in my case. When I tried v1.7, I'm failed with same problem of question. There is rare information of this problem, so my answer is restoring to older version at that time. I judged that my case help some guy. Someday, when this information is dedicated, this answer is deep downvoted. Welcome evaluation! I'm glad this discussion. Thank you sincerely! You guys are power of stackoverflow.
- Just a little tip. If you delete this answer you get back your score ;)