## How to round to 2 decimals with Python?

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I am getting a lot of decimals in the output of this code (Fahrenheit to Celsius converter).

My code currently looks like this:

def main(): printC(formeln(typeHere())) def typeHere(): global Fahrenheit try: Fahrenheit = int(raw_input("Hi! Enter Fahrenheit value, and get it in Celsius!\n")) except ValueError: print "\nYour insertion was not a digit!" print "We've put your Fahrenheit value to 50!" Fahrenheit = 50 return Fahrenheit def formeln(c): Celsius = (Fahrenheit - 32.00) * 5.00/9.00 return Celsius def printC(answer): answer = str(answer) print "\nYour Celsius value is " + answer + " C.\n" main()

So my question is, how do I make the program round every answer to the 2nd decimal place?

You can use the `round`

function, which takes as its first argument the number and the second argument is the precision after the decimal point.

In your case, it would be:

answer = str(round(answer, 2))

**How to round to 2 decimals with Python?,** How do I round to 2 decimals? In python, you have floats and decimals that can be rounded. If you care about the accuracy of rounding, use decimal type. Python's round() function requires two arguments. First is the number to be rounded. Second argument decides the number of decimal places to which it is rounded. To round the number to 2 decimals, give second argument as 2. If third digit after decimal point is greater than 5, last digit is increased by 1.

**How do I round to 2 decimals in python? · GitHub,** Example 2: Round a number to the given number of decimal places. print(round(2.665, 2)) print(round(2.675, Round Float to 2 Decimal Places in Python. To round the float value to 2 decimal places, you have to use the Python round(). The round function is the common function to use and requires only two arguments. If you want to round to 2 decimal places, you have to pass 2 as the value of the second argument.

Most answers suggested `round`

or `format`

. `round`

sometimes rounds up, and in my case I needed the *value* of my variable to be rounded down and not just displayed as such.

round(2.357, 2) # -> 2.36

I found the answer here: How do I round a floating point number up to a certain decimal place?

import math v = 2.357 print(math.ceil(v*100)/100) # -> 2.36 print(math.floor(v*100)/100) # -> 2.35

or:

from math import floor, ceil def roundDown(n, d=8): d = int('1' + ('0' * d)) return floor(n * d) / d def roundUp(n, d=8): d = int('1' + ('0' * d)) return ceil(n * d) / d

**Python round(),** Round the number n to p decimal places by first shifting the decimal point in n Python bug tracker, let me assure you that round(2.5) is supposed to return 2 . Python has several ways to round decimal digits: The round() function rounds decimal places up and down. This makes 4.458 into 4.46 and 8.82392 into 8.82. To round decimal places up we have to use a custom function.

float(str(round(answer, 2))) float(str(round(0.0556781255, 2)))

**How to Round Numbers in Python – Real Python,** Since this number doesn't make sense as a monetary figure, we use the round() function and limit the decimal places to 2, so that we can provide How do I round to 2 decimals? In python, you have floats and decimals that can be rounded. If you care about the accuracy of rounding, use decimal type. If you use floats, you will have issues with accuracy. All the examples use demical types, except for the original value, which is automatically casted as a float.

Just use the formatting with %.2f which gives you rounding down to 2 decimals.

def printC(answer): print "\nYour Celsius value is %.2f C.\n" % answer

**Built-in Functions, Python 3: abs() round() divmod ,** 2) number of digits (Optional) - number of digits up to which the given number is to be rounded. If the second parameter is missing, then round() function returns: ..a) Example 2: Round a number to given ndigits places. When you run the program, the output will be: Here, both numbers result to the same output 2.67, when 2.675 should have been rounded to 2.68. This isn't a bug but it is because, most decimal numbers cannot be represented exactly as a float.

**round() function in Python,** Call round(number, ndigits) with ndigits as 2 to round number to two decimal places. a_rounded = round(1.2345, 2). print(a_rounded). Output. 1.23. b_rounded It’s a straightforward algorithm! For example, the number 2.5 rounded to the nearest whole number is 3. The number 1.64 rounded to one decimal place is 1.6. Now open up an interpreter session and round 2.5 to the nearest whole number using Python’s built-in round() function: >>> >>>

**How to round a number to two decimal places in Python,** The context for arithmetic is an environment specifying precision, rounding rules, limits on exponents Decimals interact well with much of the rest of Python. For example, Decimal('32.100') and Decimal('0.321000e+2') both normalize to the Use combination of Decimal object and round() method. Python 3.7.3 >>> from decimal import Decimal >>> d1 = Decimal (13.949999999999999) # define a Decimal >>> d1 Decimal('13.949999999999999289457264239899814128875732421875') >>> d2 = round(d1, 2) # round to 2 decimals >>> d2 Decimal('13.95')

**9.4. decimal,** Python can do decimal calculations, too, approximately. “Decimal” implies base ten, our normal way for writing numbers with ten digits 0,1,2,3,4,5,6,7,8,9. The formatting string '.5f' means round to 5 places after the decimal point. Similarly I need to round down and it should be two decimal places. Tried the following, a = 28.266 print round(a, 2) 28.27 But the expected value is 28.26 only.

##### Comments

- A small remark regarding your code. There is no reason to have the Fahrenheit value kept as a global, it is enough (and better) to transmit it as a parameter to your functions. So, remove the "global Fahrenheit" line. In the formeln function, rename the parameter to the function "Fahreinheit" formeln(Fahreinheit). As for the rounding, you can just use the "%" parameters to display only the first 2 digits, and it should be rounded for these digits. There is no effect to the number of digits provided in the formula in formeln.
- "Note The behavior of
`round()`

for floats can be surprising: for example,`round(2.675, 2)`

gives`2.67`

instead of the expected`2.68`

." - That is called bankers rounding. It rounds towards the even number. It's in the IEEE 754 standard for floating point numbers. en.wikipedia.org/wiki/Rounding#Round_half_to_even
- I'm not sure what induced people to upvote the above comment. For the record, the fact that
`round(2.675, 2)`

gives`2.67`

rather than`2.68`

has nothing at all to do with Banker's rounding. **note**: this changes the value of answer. If you simply want to round for display, go with the answer of @Johnsyweb - stackoverflow.com/a/20457284/1498405- @Johnsyweb I'm trying it today, year's after original post and it looks working as expected. Seems round() evolved over time. See below: round(1.379, 2) -> 1.38 round(1.372, 2) -> 1.37 round(1.375, 2) -> 1.38
- This is the most useful answer IMO - keeps the actual value intact and is simple to implement! Thanks!
- Not sure why, but '{:0.2f}'.format(0.5357706) gives me '0.54' (python 3.6)
- @NoamPeled: Why shouldn't it?
`0.5357...`

is closer to`0.54`

than to`0.53`

, so rounding to`0.54`

makes sense. - I upvoted - this is what I was looking for; I like your work with python-poloniex :D
- "values are rounded to the closest multiple of 10 to the power minus ndigits;" docs.python.org/3/library/functions.html#round so no, round does not always round up, e.g.
`round(2.354, 2) # -> 2.35`

- @PeteKirkham you are right, I edited my answer to make more sense and accurate.
- -0.54 is the correct answer for rounding -0.5357706 down because it is a negative number, -0.54 < -0.53
- I would use
`10**d`

instead of`int('1' + ('0' * d))`

. - This is truncating, not rounding.