## Regex for extracting filename from path

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I need to extract just the filename (no file extension) from the following path....

\\my-local-server\path\to\this_file may_contain-any&character.pdf

I've tried several things, most based off of something like http://regexr.com?302m5 but can't quite get there

^\$$.+\$$*(.+)\.(.+)$ This regex has been tested on these two examples: \var\www\www.example.com\index.php \index.php First block "(.+\)*" matches directory path. Second block "(.+)" matches file name without extension. Third block "(.+)$" matches extension.

8.23. Extract the Filename from a Windows Path - Regular , Extract the Filename from a Windows Path Problem You have a string that holds a Selection from Regular Expressions Cookbook, 2nd Edition [Book] Attachments: Up to 2 attachments (including images) can be used with a maximum of 524.3 kB each and 1.0 MB total. * Downvoting should only be used for harmful or disrespectful posts. * Your reason will be posted as a public comment, so please be thoughtful and constructive to help educate the community.

This will get the filename but will also get the dot. You might want to truncate the last digit from it in your code.

[\w-]+\.


Update

@Geoman if you have spaces in file name then use the modified pattern below

[ \w-]+\.      (space added in brackets)


Demo

Alfred Regex to extract just the filename?, I would like to use the replace / regex function to extract just the filename, without the full path or the extension. Ive tried googling and trying a  How could I design a RegEx script which would remove a filename from a path? The trick is, the paths have all sorts of wrenches to throw into the works. Paths can consist of: 1: "Folder1/Folder2/

This is just a slight variation on @hmd's so you don't have to truncate the .

[ \w-]+?(?=\.)


Demo

Really, thanks goes to @hmd. I've only slightly improved on it.

extract file name using Regex, I was looking for a regular expression for Python capable to match a string containing a valid path, file name and extension. Finally  Hi - looking for some help using regex to extract the file name and sheet name in the full path below. The folders will always change so needs to be dynamic. Thought this would be something I could find in the community but wasn't able to.

Try this:

[^\\]+(?=\.pdf$)  It matches everything except back-slash followed by .pdf at the end of the string. You can also (and maybe it's even better) take the part you want into the capturing group like that: ([^\\]+)\.pdf$


But how you refer to this group (the part in parenthesis) depends on the language or regexp flavor you're using. In most cases it'll be smth like $1, or \1, or the library will provide some method for getting capturing group by its number after regexp match. Regex that matches path, filename and extension, Regular expression to extract filename from given path in Golang. package main import ( "fmt" "regexp" ) func main() { re := regexp.MustCompile(^(.*/)?(?:$|(.+?)  I would like to extract paths in the form of: $/Server/First Level Folder/Second_Level_Folder/My File.extension The challenge here is that the paths are embedded in a "free form" email like so: Stack Overflow If anyone is looking for a windows absolute path (and relative path) javascript regular expression in javascript for files: var path = "c:\\my-long\\path_directory\\file.html"; ((/(\w?\:?\\?[\w\-_\\]*\\+)([\w-_]+)(\.[\w-_]+)/gi).exec(path);  Output is: [ "c:\my-long\path_directory\file.html", "c:\my-long\path_directory\", "file", ".html" ]  Regular expression to extract filename from given path in Golang , dotfiles (however, will extract extension if there is one). * @param {string} path. * @return {Object} Object containing fields "dirname", "filename", "extension", and RegEx can fail if the file path is not exactly as defined in the regular expression. For example if there is no file extension specified. Or if the file extension is not exactly three characters plus the dot in length. This RegEx will guard against the two specific corner cases I just mentioned, The ultimate split path, with a single regex · GitHub, The static RegExp object is limited to 9 subsets of data; i.e.$1 through $9. Extracting numeric fields from text. Still an easy start. This example picks out numeric To extract filename from the file, we use “ GetFileName() ” method of “ Path ” class. This method is used to get the file name and extension of the specified path string. The returned value is null if the file path is null. Syntax: public static string GetFileName (string path); Parsing Path and Filename, I have different types of files that all have the date in the filename (YY-MMDD), and I need to extract only the date portion and use for further Regex flavors: .NET, Java, JavaScript, PCRE, Perl, Python, Ruby. Extract the path from a string known to hold a valid URL. Use atomic grouping to match only those URLs that actually have a path: \A # Skip over scheme and authority, if Topic: Regex & Substring() To Get Part of File Name, Hi experts, I am trying to extract File name from below path. have you tried using regex?? Pradeep_Shiv January 14, 2020, 4:38pm #3. this will return file In Logstash, you could apply the grok filter on the path field to extract the filename. If I remember correctly there are patterns for files and paths in de default grok patterns. AshishC (Ashish) December 18, 2017, 12:52am #3 ##### Comments • Which language? Some languages have a method to parse URIs in their standard library. • I'm skeptical a regex would be faster than getting the index of the last path separator, but I could be wrong. • fails: c:\fakepath\some filename with spaces.png • Fails if path contains folder names with dots in them. • Requirement is filename without extension. You can post a separate question for you needs • This worked for related question of mine (file name with extension, but none of the directories -- just add [\w-]*$ after \. -- this also removes issue with having a dot in a folder name).
• Should it be more like: [^\\](.+)\.pdf$ • @macduff the question is also the path or just the filename..? • I understood it to be the filename, but not the extension or path, sorry if I misunderstood. • @KL-7 Thanks, but I don't want the .pdf. I tried using [^\\]+[^.pdf]$` and that concept didn't work