Swift - Get 10's place of a decimal number

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How can I get 10's place of a decimal number in Swift?

Ex:

  • 1.20 -> 10
  • 1.90 -> 10
  • 5.50 -> 10

  • 20.30 -> 30

  • 25.50 -> 30
  • 29.00 -> 30

  • 90.0 -> 90

  • 90.1 -> 100
  • 95.50 -> 100
  • 99.01 -> 100

  • 120.0 -> 120

  • 121.1 -> 130
  • 129.5 -> 130

This is basically ceil operation, you just have to move the decimal point (divide by 10 and then multiply by 10):

func ceilTo10(_ value: Double) -> Int {
    return Int(ceil(value / 10) * 10)
}

print(ceilTo10(1.20)) // 10
print(ceilTo10(90.0)) // 90
print(ceilTo10(121.1)) // 130

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Use rounded(.up). Here's a helpful extension:

extension BinaryFloatingPoint {
    func roundedUpNearest10() -> Self {
        return (self / 10).rounded(.up) * 10
    }
}

for num in [ 1.2, 1.9, 5.5, 20.3, 25.5, 29, 90, 90.1, 95.5, 99.01, 120, 121.1, 129.5 ] {
    print(num, num.roundedUpNearest10())
}

Output:

1.2 10.0 1.9 10.0 5.5 10.0 20.3 30.0 25.5 30.0 29.0 30.0 90.0 90.0 90.1 100.0 95.5 100.0 99.01 100.0 120.0 120.0 121.1 130.0 129.5 130.0

If you actually want an Int result, update the extension:

extension BinaryFloatingPoint {
    func roundedUpNearest10() -> Int {
        return Int((self / 10).rounded(.up) * 10)
    }
}

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You can use ceil with this formula 10 is nearest 10

Example:

    print(10 * Int(ceil(95.50 / 10)))
    print(10 * Int(ceil(99.1 / 10)))
    print(10 * Int(ceil(99.01 / 10)))
    print(10 * Int(ceil(129.5 / 10)))
    print(10 * Int(ceil(121.1 / 10)))

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Comments
  • So you want to round up to nearest 10?
  • Yes, nearest 10th multiplication number. @Sweeper