Regex to format IPv6 address - remove leading zeroes

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Say I have an IPv6 address like:

2001:04E8:0000:4001:0000:0000:0000:0000/64

And I want output like

2001:4E8:0:4001:0:0:0:0/64

So basically, it removes leading zeroes and at the same time, replaces four zeroes with a single zero.

replaceAll("(:(0)*)|(^0+)",":")

the above regex does the job, but gives output as

2001:4E8::4001::::/64

The four zeroes are all omitted.

Note: Input maybe ANY valid ipv6 address


You can use REPLACE twice and SUBSTR to remove leading 0.

SELECT ipv6,
       SUBSTR(REPLACE(REPLACE(':' || ipv6, ':00', ':'),':0', ':'),2) AS result
FROM tab;

SqlFiddleDemo

Demo is using MySQL because Oracle is not responding. The only change is string concatenation.

Output:

╔═════════════════════════════════════════════╦════════════════════════════╗
║                    ipv6                     ║           result           ║
╠═════════════════════════════════════════════╬════════════════════════════╣
║ 2001:04E8:0000:4001:0000:0000:0000:0000/64  ║ 2001:4E8:0:4001:0:0:0:0/64 ║
║ 0000:0001:0012:0123:1234:0000:0000:0000/64  ║ 0:1:12:123:1234:0:0:0/64   ║
║ 0001:04E8:0000:4001:0000:0000:0000:0000/64  ║ 1:4E8:0:4001:0:0:0:0/64    ║
║ 0012:04E8:0000:4001:0000:0000:0000:0000/64  ║ 12:4E8:0:4001:0:0:0:0/64   ║
║ 0123:04E8:0000:4001:0000:0000:0000:0000/64  ║ 123:4E8:0:4001:0:0:0:0/64  ║
╚═════════════════════════════════════════════╩════════════════════════════╝

java - Regex to remove leading zero for any ipv6 address, I can give you a simple solution : String subjectString="2001:0DB8:0:0:0476::"; String resultString = subjectString.replaceAll("(:(0)*)|(^0+)",":");  Stephen Ryan at Dartware has produced a regular expression (regex) that can be used to match any legal format of an IPv6 address. This is useful for determining whether a particular string is, in fact, a legal IPv6 address.


Sample using Oracle's Regexp_Replace:

   SQL> with t as (
  2  select '2001:04E8:0000:4001:0000:0000:0000:0000/64' str from dual union all
  3  select '0000:0001:0012:0123:1234:0000:0000:0000/64' from dual union all
  4  select '0001:04E8:0000:4001:0000:0000:0000:0000/64' from dual union all
  5  select '0000:0001:0012:0123:1234:0000:0000:0000/64' from dual
  6  ) -- end of sample data
  7  select regexp_replace(str, '(:|^)(0{0,3})([1-9]*)', '\1\3') str
  8    from t;
STR
--------------------------------------------------------------------------------
2001:4E8:0:4001:0:0:0:0/64
0:1:12:123:1234:0:0:0/64
1:4E8:0:4001:0:0:0:0/64
0:1:12:123:1234:0:0:0/64

Remove leading zeroes from IP address, way to remove leading zeroes from IP addresses. Source: https://autohotkey.​com/board/topic/15491-regex-to-strip-leading-zeroes-out-of-an-ip-address-octet/ If you have a “hextet” with 4 zeros then you can remove those and leave a single zero. Your IPv6 device will add the remaining 3 zeros. When we talk about IPv4 addresses, we use the term “octet” to define a “block” of 8 bits. In IPv6, there is no official term (yet) and there is an IETF draft that discusses


In java, something like this works:

replaceAll("(:000)|(:0*)", ":");

8.17. Matching IPv6 Addresses, Matching IPv6 Addresses Problem You want to check whether a string represents a valid IPv6 address using the Selection from Regular Expressions Cookbook, 2nd Edition [Book] Leading zeros are optional. We have to remove the check at the start of the regex that keeps it from finding IPv6 addresses within longer  The first hex number is separated from the rest by dual colons. There may also be a trailing subnet mask, such as /64. Example, my Linux system IPv6 address is (numbers changed to keep people off my network) ff80::215:77ff:ff81:fff8/64. Note that leading 0's are truncated, so instead of 0215 for the second term,


Try this one:

WITH t AS (
  SELECT '2001:04E8:0000:4001:0000:0000:0000:0000/64' str FROM dual UNION ALL
  SELECT '0000:0001:0012:0123:1234:0000:0000:0000/64' FROM dual UNION ALL
  SELECT '0001:04E8:0000:4001:0000:0000:0000:0000/64' FROM dual UNION ALL
  SELECT '0000:0001:0012:0123:1234:0000:0000:0000/64' FROM dual UNION ALL
  SELECT '2001:04E8:0000:4001:0000:0:0000:0/64' FROM dual
  )
SELECT 
    REGEXP_REPLACE(str, '(:|^)0+([[:xdigit:]]+)', '\1\2')
from t;

2001:4E8:0:4001:0:0:0:0/64
0:1:12:123:1234:0:0:0/64
1:4E8:0:4001:0:0:0:0/64
0:1:12:123:1234:0:0:0/64
2001:4E8:0:4001:0:0:0:0/64

6.6. Strip Leading Zeros, 6.6. Strip Leading Zeros Problem You want to match an integer number, and either return the number without any leading zeros or delete the leading zeros. Match an IPv6 address in standard notation, which consists of eight 16-bit words using hexadecimal notation, delimited by colons (e.g.: 1762:0:0:0:0:B03:1:AF18). Leading zeros are optional. Leading zeros are optional.


Python Exercises: Remove leading zeros from an IP address , Python Regular Expression: Exercise-16 with Solution. Write a Python program to remove leading zeros from an IP address. Sample Solution:-. For example, "2001:0db8:0000:0000:0000:ff00:0042:8329" IPv6 address. For convenience, an IPv6 address may be abbreviated to reduce its length using these rules. One or more leading zeroes from any groups of hexadecimal digits are removed; this is usually done to either all or none of the leading zeroes. For example, the above IPv6 address can be abbreviated as: "2001:db8:0:0:0:ff00:42:8329".


Python, Given an IP address, remove leading zeros from the IP address. Python program to remove leading zeros an IP address and print the IP using regex Address · Python program to validate an IP Address · Python PyTorch zeros() method  Regular Expression to For documents numbers (serie, numeration, etc). Number with leading zeros Regex Tester isn't optimized for mobile devices yet. You can


Python Regex, Python Regex example: Here, we are going to learn how to remove leading zeros from an IP address using Python program? In Linux you can use regular expressions with grep to extract an IP address from a file. The grep command has the -E (extended regex) option to allow it to interpret a pattern as a extended regular expression. The format of an IPv4 address is a 32-but numeric address, grouped 8 bits at a time (called an octet), each separated by a dot.