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Hi I am very new for android and in my app I have Validations for Change password page.

That means the Password must contain minimum 8 characters at least 1 Alphabet, 1 Number and 1 Special Character, for this I tried the code below, but it's not working.

Please help me.

if(!isPasswordValidMethod(newPassword.getText().toString())){
           System.out.println("Not Valid");

                }else{

        System.out.println("Valid");
    }



     // Validate password
        private boolean isPasswordValidMethod(String password) {

            String yourString = newPassword.getText().toString();

            System.out.println("yourString is =" + yourString);

            boolean isValid = false;

            // ^[_A-Za-z0-9-\+]+(\.[_A-Za-z0-9-]+)*@[A-Za-z0-9-]+(\.[A-Za-z0-9]+)*(\.[A-Za-z]{2,})$
            // ^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$

            String expression = "^(?=.*[A-Za-z])(?=.*\\\\d)(?=.*[$@$!%*#?&])[A-Za-z\\\\d$@$!%*#?&]{8,}$";
            CharSequence inputStr = password;

            Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
            Matcher matcher = pattern.matcher(inputStr);
            if (matcher.matches()) {
                System.out.println("if");
                isValid = true;
            }else{
                System.out.println("else");
            }
            return isValid;
        }

try following Code

 //*****************************************************************
public static boolean isValidPassword(final String password) {

    Pattern pattern;
    Matcher matcher;
    final String PASSWORD_PATTERN = "^(?=.*[0-9])(?=.*[A-Z])(?=.*[@#$%^&+=!])(?=\\S+$).{4,}$";
    pattern = Pattern.compile(PASSWORD_PATTERN);
    matcher = pattern.matcher(password);

    return matcher.matches();

}

And change your code to this

   if(newPassword.getText().toString().length()<8 &&!isValidPassword(newPassword.getText().toString())){
        System.out.println("Not Valid");
      }else{
       System.out.println("Valid");
    }

Validate Password from text input - Android Studio Tutorial, Download my Game here: https://goo.gl/Ma9bY2 ▻Twitter: https://goo.gl/3fzWnC ▻Instagram: https Duration: 7:48 Posted: Mar 21, 2018 It's ok to use a toast for the result of the registration, when all form fields are valid. Creating account with invalid input. Before calling mAuth.createUserWithEmailAndPassword, the only validation that's really enforced is that the confirmation password is not empty. That's strange.

public static boolean isValidPassword(String s) {
            Pattern PASSWORD_PATTERN
                    = Pattern.compile(
                    "[a-zA-Z0-9\\!\\@\\#\\$]{8,24}");

            return !TextUtils.isEmpty(s) && PASSWORD_PATTERN.matcher(s).matches();
        }

to use it,

if(isValidPassword(password)){ //password valid}

You can set whatever symbol that you allowed here

Validate Email & Password with Regular Expression, Validate Email & Password with Regular Expression - Android Studio a string and then Duration: 10:02 Posted: May 24, 2018 In this tutorial, we show you how to use XML to create a password field, label field and a normal button. When you click on the button, the password value will be displayed as a floating message (toast message). P.S This project is developed in Eclipse 3.7, and tested with Android 2.3.3. 1. Custom String

public static boolean passwordCharValidation(String passwordEd) {
    String PASSWORD_PATTERN = "^(?=.*[A-Z])(?=.*[@_.]).*$";
    Pattern pattern = Pattern.compile(PASSWORD_PATTERN);
    Matcher matcher = pattern.matcher(passwordEd);
    if (!passwordEd.matches(".*\\d.*") || !matcher.matches()) {
        return true;
    }
    return false;
}

Email and Password validation in android studio, This makes the application smart and fast. This video tutorial will teach you how to validate Duration: 12:56 Posted: Sep 4, 2017 Secondly, instead of checking for a list of special characters, you could flip it and check if the password contains any characters that are neither letters of the latin alphabet (a-zA-Z) nor digits (0-9).

Try this it works

   public static boolean isPasswordValidMethod(final String password) {

    Pattern pattern;
    Matcher matcher;
    final String PASSWORD_PATTERN = "^(?=.*[A-Za-z])(?=.*\\\\d)(?=.*[$@$!%*#?&])[A-Za-z\\\\d$@$!%*#?&]{8,}$""
    pattern = Pattern.compile(PASSWORD_PATTERN);
    matcher = pattern.matcher(password);

    return matcher.matches();

}

Validate Email & Password (Regular Expressions), In this video we will learn, how to validate an email address and password client developer Duration: 10:02 Posted: May 24, 2018 listen to changes to the field's content and run validation of that specific field or; listen to the submit-button click and validate the content of all fields on submit. Else validation is just the same as in every other Java app: just test your constraints. BTW: your question was already answered on stackoverflow.

  String validPassword = "12345";
                     _Password_String = Password.getText().toString();
                    Matcher matcher = Pattern.compile(validPassword).matcher(_Password_String);
                    if (matcher.matches()) {
                        Log.e("d11", _Password_String);
                        Toast.makeText(getActivity(), "Password Match", Toast.LENGTH_LONG).show();
                        getFragmentManager().popBackStack();


                    } else {
                        Password.setError("Password");
                        Toast.makeText(getActivity(), "Password not Match", Toast.LENGTH_LONG).show();
                    }

Password and confirm password validation in Android Studio, Inconsistent UX. Most validation errors call setError of the relevant input field. An exception is when the confirmation password doesn't match  Password validation. The View class used for password input and validation is generally the same as for the email. We want to make the password input visible and invisible, through a toggle. Android provides this through their support library, yay! 🎉 Meet TextInputLayout, and TextInputEditText.

How to validate password with regular expression – Mkyong.com, match anything with previous condition checking {6,20} # length at least 6 characters and maximum of 20 ) # End of group Password validator Testing * @author mkyong * */ public class Wicket password field example. How to Validate Email and Password in Android. Unsubscribe from Gadgets and Technical field Android Tech? Cancel Build iOS and Android Apps with Google's Flutter & Dart

Android password field example – Mkyong.com, In this tutorial, we show you how to use XML to create a password field, label field and a normal button. When you click on the button, the 

Password Validation Animation -Android, Ever got annoyed by the 'high standards' of the password you are bound to set these days? Here is a concept of a small delighter. Inspired by this article on 

Comments
  • Maybe this answer will help you: stackoverflow.com/questions/9962382/…
  • if(newPassword.getText().toString().length()<8 ||!isValidPassword(newPassword.getText().toString())){ System.out.println("Not Valid");
  • that is validate condition
  • minimum 8 characters means it must be "&&" not ||
  • What would be conditions for this pattern like password must contain min 8 characters, must be alpha numeric,must contain at least one symbol. Like this? @mdDroid
  • For anyone that wants to know ... The regex represents the need for user to enter atleast 1 Uppercase, 1 Number and 1 Symbol.
  • Is you answer full-fill :It contains minimum 8 characters at least 1 Alphabet, 1 Number and 1 Special Character.Thanks
  • yes Firstly check passwordEd length greater then 8 if(passwordEd.length() > 8);