## Counting how many times each vowel appears

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I've written a little program to count how many times each vowel appears in a list, but it's not returning the correct count, and I can't see why:

```vowels = ['a', 'e', 'i', 'o', 'u']
vowelCounts = [aCount, eCount, iCount, oCount, uCount] = (0,0,0,0,0)
wordlist = ['big', 'cats', 'like', 'really']

for word in wordlist:
for letter in word:
if letter == 'a':
aCount += 1
if letter == 'e':
eCount += 1
if letter == 'i':
iCount += 1
if letter == 'o':
oCount += 1
if letter == 'u':
uCount += 1
for vowel, count in zip(vowels, vowelCounts):
print('"{0}" occurs {1} times.'.format(vowel, count))
```

The output is

```"a" occurs 0 times.
"e" occurs 0 times.
"i" occurs 0 times.
"o" occurs 0 times.
"u" occurs 0 times.
```

However, if I type `aCount` in the Python shell, it gives me `2`, which is correct, so my code has indeed updated the aCount variable and stored it correctly. Why isn't it printing the correct output?

The problem is with this line:

```vowelCounts = [aCount, eCount, iCount, oCount, uCount] = (0,0,0,0,0)
```

`vowelCounts` does not get updated if you start incrementing `aCount` later.

Setting `a = [b, c] = (0, 0)` is equivalent to `a = (0, 0)` and `[b, c] = (0, 0)`. The latter is equivalent to setting `b = 0` and `c = 0`.

Reorder your logic as below and it will work:

```aCount, eCount, iCount, oCount, uCount = (0,0,0,0,0)

for word in wordlist:
for letter in word:
# logic

vowelCounts = [aCount, eCount, iCount, oCount, uCount]

for vowel, count in zip(vowels, vowelCounts):
print('"{0}" occurs {1} times.'.format(vowel, count))
```

Program to count vowels in a string (Iterative and Recursive , See your article appearing on the GeeksforGeeks main page and help other Geeks. Please write comments if you find  This program asks the user to enter a sentence and the letter they want to count the number of times it appears in the string. of times a specific letter appears in a string Count Vowels

You can also use collections counter (which is the natural go-to function when counting things, it returns a dictionary):

```from collections import Counter

vowels = list('aeiou')
wordlist = ['big', 'cats', 'like', 'really']

lettersum = Counter(''.join(wordlist))

print('\n'.join(['"{}" occurs {} time(s).'.format(i,lettersum.get(i,0)) for i in vowels]))
```

Returns:

```"a" occurs 2 time(s).
"e" occurs 2 time(s).
"i" occurs 2 time(s).
"o" occurs 0 time(s).
"u" occurs 0 time(s).
```

lettersum:

```Counter({'l': 3, 'a': 2, 'e': 2, 'i': 2, 'c': 1, 'b': 1,
'g': 1, 'k': 1, 's': 1, 'r': 1, 't': 1, 'y': 1})
```

Count the number of vowels occurring in all the substrings of given , Find the path from root to the given nodes of a tree for multiple queries a' occurred 3 times) A simple solution is for each substring, we count the occurrences of the See your article appearing on the GeeksforGeeks main page and help  In this program ill teach you how to count the number of vowels in a string that the user inputs. Email: beginnerprogramsyt@gmail.com If you have a introductory program (c++ or Java or other) that

You can use a dictionary comprehension:

```vowels = ['a', 'e', 'i', 'o', 'u']
wordlist = ['big', 'cats', 'like', 'really']
new_words = ''.join(wordlist)
new_counts = {i:sum(i == a for a in new_words) for i in vowels}
```

Output:

```{'a': 2, 'e': 2, 'i': 2, 'o': 0, 'u': 0}
```

Python Program to Count the Number of Each Vowel, In this program, you'll learn to count the number of each vowel in a string using dictionary and list comprehension. Suppose you want to find out how many times particular text or a number value occurs in a range of cells. For example: If a range, such as A2:D20, contains the number values 5, 6, 7, and 6, then the number 6 occurs two times.

In addition to what @jpp said simple datatypes like integers are returned by value not by reference so when you assign it to something and change that something it doesn't get affected

```a = 10
b = a #b=a=10
b = 11 #b=11, a=10
print a, b
--> 10 11
```

I'd have made this a comment to his but I need reputation to do that :D

How to count the vowels in a string in Python, Use str.count() to count vowels in a string. The vowels in the string "AEIOU" count as different characters than the vowels in the to provide you with code completions in real time sorted by relevance. At this point we have a list of pairs, where each pair contains a word and its frequency. This list is a bit redundant. If ‘the’ occurs 500 times, then this list contains five hundred copies of the pair (‘the’, 500). The list is also ordered by the words in the original text, rather than listing the words in order from most to least frequent.

Java exercises: Count all vowels in a string, Write a Java method to count all vowels in a string. Sample MILLISECONDS.​convert(time, TimeUnit. In this program, we need to count the number of vowels present in a string and display those vowels. This can be done using various methods. In this article, we will go through few of the popular methods to do this in an efficient manner.

Program to Count the Total Number of Vowels and Consonants in a , If any character lies between 'a' and 'z' except vowels, then increment the count for ccount by 1. Print both the counts. Read from a .txt file that has different words on separate lines. Determine how many vowels each word has, and print each word AND vowel count to the console. You must write and use a function outside of main(). Here's the code I wrote:

Python Program to Count the Number of Vowels in a String , The program output is also shown below. The count is incremented each time a vowel is encountered. 6. Next - Python Program to Read a List of Words and Return the Length of the Longest One. In this video i show you how to make a program that counts how many times each distinct word appears in the input given by the user. I use sort function to sort the input by dictionary order, and