I have an Object and I want seperate Object from given Object

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const myjson = {
  "productname0": "Test1",
  "price0": "10",
  "categories0": "61",
  "type0": "Physical",
  "availability0": "available",
  "weight0": "0.5",
  "productname1": "Test2",
  "price1": "20",
  "categories1": "61",
  "type1": "Physical",
  "availability1": "available",
  "weight1": "0.7",
}

I have an Object and I want to separate object. All the key value which has last number 0 it has own json, for 1 it has own json.

I want this result

[{
  "productname0": "Test1",
  "price0": "10",
  "categories0": "61",
  "type0": "Physical",
  "availability0": "available",
  "weight0": "0.5",
},
{
  "productname1": "Test2",
  "price1": "20",
  "categories1": "61",
  "type1": "Physical",
  "availability1": "available",
  "weight1": "0.7",
}]

Try like this

const myjson = {
  "productname0": "Test1",
  "price0": "10",
  "categories0": "61",
  "type0": "Physical",
  "availability0": "available",
  "weight0": "0.5",
  "productname1": "Test2",
  "price1": "20",
  "categories1": "61",
  "type1": "Physical",
  "availability1": "available",
  "weight1": "0.7",
}

var finalArray=[];
Object.keys(myjson).forEach(function(value){
if(value.endsWith("0")){
    if(!finalArray[0]){
        finalArray[0]={};
    }
    finalArray[0][value]=myjson[value];
} else if(value.endsWith("1")) {
    if(!finalArray[1]){
        finalArray[1]={};
    }
    finalArray[1][value]=myjson[value];
}

});
console.log(finalArray);

Update :

const myjson = {
  "productname0": "Test1",
  "price0": "10",
  "categories0": "61",
  "type0": "Physical",
  "availability0": "available",
  "weight0": "0.5",
  "productname1": "Test2",
  "price1": "20",
  "categories1": "61",
  "type1": "Physical",
  "availability1": "available",
  "weight1": "0.7",
}

var finalArray=[];
Object.keys(myjson).forEach(function(value){

var lastChar = value[value.length -1];

    if(!finalArray[lastChar]){
        finalArray[lastChar]={};
    }
    finalArray[lastChar][value]=myjson[value];

});
console.log(finalArray);

Split object key/value pairs into separate objects, Sounds like you want Array.prototype.reduce() . let grades = [5,5,6,7,6,7,9,10,8,6]; let finalSpread = grades.reduce((spread, grade) => { let count  GiftCouponPayment and Payment are autogenerated classes and these objects are created by ORM. I have added more functionality to these classes by using partial classes. Note: In database each PaymentComponent (E.g. GiftCouponPayment) has its own properties

Hey I have a working solution for you if you want to try it :

var Data = [];
for (var i = 0; i < (Object.keys(myjson).length) / 6; i++) 
{ 

Data.push({ 
"productname": myjson["productname" + i], 
"price": myjson["price" + i], 
"categories": myjson["categories" + i],
 "type": myjson["type" + i], 
"availability": myjson["availability" + i], 
"weight": myjson["weight" + i] 
}); 

}
console.log(Data);

Object methods, "this", So, here we've got a method sayHi of the object user . This section covers an advanced topic, to understand certain edge-cases better. it's useful when we actually do not want to have a separate this , but rather to take it  In your document, select the object with which you want to work, switch to the “Layout” menu, and then click the “Position” button. That button also appears on the “Format” menu of the Ribbon and works the same way. The Position drop-down menu is divided into two sections: “In Line With Text”

Let's say you have this input :

const myJSON = {
  "productname0": "Test1",
  "price0": "10",
  "categories0": "61",
  "type0": "Physical",
  "availability0": "available",
  "weight0": "0.5",
  "productname1": "Test2",
  "price1": "20",
  "categories1": "61",
  "type1": "Physical",
  "availability1": "available",
  "weight1": "0.7",
}

You want to separate the properties according to the last character on the keys.

So you create an array containing your result, and them loop over the input's keys using Object.keys

For each key, separate the last character, because this will be your result index. Also check if the result array contains an object at that index already, or create an empty object if not.

Then you have this :

const result = [];

Object.keys(myJSON).forEach(key => {
    if (result[key[key.length-1]] === undefined) {
        result[key[key.length-1]] = {};
    }
    result[key[key.length-1]][key] = myJSON[key];
})

This solution will work for any input object, given that the keys / properties have the index at the end of their name.

Transforming one collection of objects into a separate unrelated , A domain object specific collection is a class which represents a collection place that transformation logic into CustomerByAgeFactory class if you want to You could have separate objects to implement your groupers and  Software objects also have a state and a behavior. A software object's state is stored in fields and behavior is shown via methods. So in software development, methods operate on the internal state of an object and the object-to-object communication is done via methods. Classes in Java. A class is a blueprint from which individual objects are created.

You could make use of the reduce function, something like this:

const parameterNames = ['productname', 'price', 'categories', 'type', 'availability', 'weight'];
const data = Object.keys(myjson).reduce((acc, key) => {
  let parameterName = null;
  for (let i = 0; i < parameterNames.length; i++) {
      if (key.indexOf(parameterNames[i]) > -1) {
         parameterName = parameterNames[i];
         break;
      }
  }

  if (parameterName) {
    let index = key.split(parameterName)[1];

    if (acc[index] === undefined) {
      acc[index] = {};
    }

    acc[index][parameterName] = myjson[key];
  }    

  return acc;
}, []);

How can I use an array modifier to create individually manipulatable , If original object consists from more parts (like Monkey head + 2eyes) you will the use of the Array modifier that don't suffer from the separate parts issue. + A . But can alternatively use a Group of objects and have them spread around in  The Object constructor creates an object wrapper for the given value. If the value is null or undefined, it will create and return an empty object, otherwise, it will return an object of a Type that corresponds to the given value. If the value is an object already, it will return the value.

JavaScript object basics, While working with this example you should have your developer tools Let's update the JavaScript object in our file to look like this: The live version will give you a blank screen, but that's OK — again, open your devtools Each name​/value pair must be separated by a comma, and the name and value  Whether you can or can't see the object. In fact, most objects have several properties, with each property determining a different characteristic of the object. Richard Mansfield explains, in Mastering VBA for Microsoft Office 2013, how objects of the same type have the same set of properties. However, each of the individual objects stores

Object.create(), The Object.create() method creates a new object, using an existing object as the with ES2015 Accessors our code can look like this get() { return 10; } display top-level property name:value pairs of given object function  Explanation: We have been asked to do deep copy of object so What's basically it's mean ??. Let's understand in this way you have been given an object personalDetail this object contains some property which again a type of object here as you can see address is an object and phoneNumber in side an address is also an object.

Data Structures: Objects and Arrays :: Eloquent JavaScript, We've seen a few suspicious-looking expressions like myString.length (to get the Inside the braces, there is a list of properties separated by commas. You give it an object, and it returns an array of strings—the object's property names.

Comments
  • That is not JSON. Please read What is the difference between JSON and Object Literal Notation?
  • do you want to separate object into array( list of objects) based on last number?
  • What have you tried so far ?
  • do you want to separate object into array( list of objects) based on last number? – yes
  • The result you say you want is not valid syntax. Is there supposed to be an array there?
  • for each new you have to add logic! is that not fixed?
  • check my updated answer, anyway you have to use little logic to direct correct position
  • if you are sure about that last character will be the integer always, then you can try my updated solution!
  • I don't think that you can assume that the index will be less than 10, i.e. a single character at the end
  • Thank you TBenchikhi.