Find the first row where all three values have increased

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write the pandas program to select the specified columns and the rows from a given data frame?

Given this dataset

declare @TestData Table
  Time int,
  Temp_Front int, 
  Temp_Center int, 
  Temp_Back int

insert into @TestData 
    (2, 26, 27, 27), 
    (3, 26, 28, 27), 
    (4, 27, 28, 27), 
    (5, 27, 28, 28);

select Time ,
  Temp_Front , 
  Temp_Center , 
  Temp_Back   from @TestData

I need to find the first row where all three Temp value are greater than the temp values of the first row.

So Temp_Front > 26, Temp_centre > 27, Temp_back > 27.

I've tried a lot of stuff and I always ends up with a lot of variables. And a lot of mess.

I won't mud the picture with this. So I just included the problem and the dataset.

Interesting. I would approach this as:

with first_row as (
      select top (1) td.*
      from @testdata td
      order by time
select top (1) td.*
from @testdata td cross join
     first_row fr
where td.temp_front > fr.temp_front and
      td.temp_center > fr.temp_center and
      td.temp_back > fr.temp_back
order by time asc;

I don't find that window functions are particularly helpful for this problem.

If you were to use window functions:

select top (1) td.*
from (select td.*,
             first_value(temp_front) over (order by time) as fr_temp_front,
             first_value(temp_center) over (order by time) as fr_temp_center,
             first_value(temp_back) over (order by time) as fr_temp_back
      from @testdata td
     ) td
where td.temp_front > fr_temp_front and
      td.temp_center > fr_temp_center and
      td.temp_back > fr_temp_back
order by time asc;

Pandas: Get the first 3 rows of a given DataFrame, Write a Pandas program to get the first 3 rows of a given DataFrame. DataFrame(exam_data , index=labels) print("First three rows of the data  As you can see in the below screenshot, all of the rows that have identical values in the first 3 columns have been located (first occurrences are not identified as duplicates). If you want more options to dedupe your worksheets, use the Duplicate Remover wizard that can find duplicates with or without first occurrences as well as unique values.

Calculate row numbers and use conditional aggregation to get the values on the first row. This can then be used for comparison to get the first such row which meets the criteria mentioned using TOP and ORDER BY.

with first_row as 
  select t.*, row_number() over(order by time) as rnum from @TestData t
select top 1 Time, Temp_Front, Temp_Center, Temp_Back
        select f.*, 
                max(case when rnum=1 then Temp_Front end) over() as first_tempfront,
                max(case when rnum=1 then Temp_Center end) over() as first_tempcenter,
                max(case when rnum=1 then Temp_Back end) over() as first_tempback
        from first_row f
    ) Dummy
  temp_front > first_tempfront and temp_center > first_tempcenter and temp_back > first_tempback
order by rnum

Essential Algorithms: A Practical Approach to Computer Algorithms , Similarly, the ArrayEntry objects are stored in increasing order of The first RowEntry object in the first row might represent column 100, and the first RowEntryy To find a particular value, look down the row list until you find the right row. in Figure 4.6, you still need to write algorithms to perform three array operations. 1. If you want only the first row number, you can use the MIN function to extract just the first row number, which will be the lowest number in the array. Simple version. Entered in a single cell, the ROW function will display only the first row number, even though it returns an array.

Sorry for the late response. You may use this:

;with [min] as (
    select top 1 
        [Time], [Temp_Front], [Temp_Center], [Temp_Back] 
    order  by 
         [Time] asc     
select top 1 
    [t].[Time], [t].[Temp_Front], [t].[Temp_Center], [t].[Temp_Back] 
    @TestData   as [t]
cross join
    [min]       as [m]
        ([t].[Time]         <>  [m].[Time])
    and [t].[Temp_Front]    >   [m].[Temp_Front]            
    and [t].[Temp_Center]   >   [m].[Temp_Center]
    and [t].[Temp_Back]     >   [m].[Temp_Back]
order by [Time] asc;

Full testing query:

Lookup multiple criteria in rows or columns - Xelplus, When using the Index Match approach, the first thing you identify is the map or the area that The MATCH() function is used to find at what row number the lookup value is found. 1 = less than; 0 = exact match; -1 = greater than There are other ways to resolve this problem but I find these three to be the simplest ways. Notice the return array (C8:E15) includes 3 columns: First, Last, Department. All three values are returned and spill into the range C5:E5. Example #4 - two-way lookup. XLOOKUP can be used to perform a two-way lookup, by nesting one XLOOKUP inside another. In the example below, the "inner" XLOOKUP retrieves an entire row (all values for Glass

JOIN to a derived table consisting of only the first row, and check all three columns in the WHERE clause or JOIN condition. Use TOP 1 to get only the first row that satisfies the condition.

Discrete Wavelet Transform: A Signal Processing Approach, For a data length 8 and three levels of decomposition, there are 52 + 1= 26 Example 12.2 Find the 3-level DWPT of {3,4,2,4,4,5,1,7} Let the cost function be the there are seven coefficients with magnitude greater than 1 in the first row of​  1. To count first n numeric strings in a row, use this formula =COUNT(OFFSET(A20,0,0,1,A23) ). 2. In above formulas. A20 is the first value in the row you want to calculate, A23 indicates to count or sum first n values, you can change them as you need.

If, i understand correctly you can also use sum of temp values

with cte as (
    select *, (select sum(temp_values) 
               from (values (Temp_Front), (Temp_center), (Temp_back))a(temp_values)) as Maxnum
    from  @TestData t

select * 
from cte c
where Maxnum = (select MAX(Maxnum) from cte);

Production Management and Business Development: Proceedings of the , where all three risks categories have a zero probability of occurrence), along The first row of values corresponding to a given supplier represent its network, The supplier risk profiles can be used to determine those risk events which have Overleaf, suppliers who have experienced increases in network, operational,  However I have a different challenge now: to make it work for 7 columns, where I may select only some of them to make this analysis. The way the formula is will only return me a value which is common for all the 7columns. Id like to have the chance to select 2 or 3 columns for instance (out of those 7) to apply the search.

Match two criteria and return multiple records, I have a table of 3 columns (Security name, date, price) and I have to find the price If I work with vlookup or Index-match I got only the first price for certain securities. Extract all rows from a range that meet criteria in one column [Array formula] a price based on the criteria mentioned, this formula would be more simpler. In a blank cell besides your data, please enter this formula: =AND (EXACT (A1:D1,A1)), ( A1:D1 indicates the cells that you want to compare, and A1 is the first value in your data range)see screenshot: 2. Then press Ctrl + Shift + Enter keys together to get the result, if the cell values are equal,

Get rows having different values for a column based on the duplicate , So both these rows to be listed in output. But rows 2 and 4 has unique combination for first 3 columns but they have same values in DEF column. Some problems require information about the locations of the array elements that meet a condition rather than their actual values. In this example, you can use the find function to locate all of the elements in A less than 9.

Mining Reporter, The tray itself is 11% inches long and 6 inches wide, and has a raised edge to keep the cupels Iron and fire-clay trays were tried but not found to be serviceable Air is admitted only near the top of the mouth of the mufile, and the front row of +l_1 three swings are observed, then L: ,but the latter value of L is not quite so  Second row: 2 + x squared, 3 negative x. The last 3 rows are the same: 2 negative x, 3 negative. An algebra tile configuration. 5 tiles are in the Factor 1 spot: 2 +x , 3 +. 5 tiles are in the Factor 2 spot: 2 +x, 3 +. 25 tiles are in the Product spot in 5 columns with 5 rows. First row: 2 + x squared, 3 + x. Second row: 2 + x squared, 3

  • how do you define first row?
  • I'm assuming 'first row' is determined by the 'time' field?
  • Correct Daniel. Sorry for omitting that.
  • Hmmn the price of the one with window function is only half compared to the cross join function
  • You need to handle case, when first row is max row. You shouldnt display it. My answer was very same, this case handled. And, my query was written originally by me. Its very strange, why our answers became very same :)
  • @JensBorrisholt . . . Interesting about the performance. Do you have an index on time? With such an index, I would expect the first version to have the better performance.
  • This answer is much more complicated than it needs to be. For instance, first_value() would simplify the logic.
  • totally missed it..just saw you added in a version with first_value.
  • I like the version with FIRST_VERSION better because it's simpler :)
  • I've looked at this post… Which basically does what you are suggestion. But I cant get it to work (compile)
  • Can you add your attempt to use this strategy to your question, and the error you got, so we can see where you went wrong and fix it?
  • @JensBorrisholt btw, Gordon's answer, which you accepted, is exactly what I was suggesting in my answer.
  • Then I haven't been clear enough! I can not use a sum, because I need to be sure that all three values have increased not only the sum of them.
  • That was more or less where I started :)