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how to remove text before a specific character in excel

I'm new to python and am having difficulties to remove words in a string

9 - Saturday, 19 May 2012

above is my string I would like to remove all string to

19 May 2012

so I could easily convert it to sql date

here is the could that I tried

new_s = re.sub(',', '', '9 - Saturday, 19 May 2012')

But it only remove the "," in the String. Any help?

You can use string.split(',') and you will get

['9 - Saturday', '19 May 2012']

How to remove text after a specific character in Excel, Assuming that you have a text string that contains email address in Cell B1, and if you want to extract word that begins with a specific character “  Delete texts before or after specific character by Find and Replace in Excel. For removing all texts before or after a specific character with the Find and Replace function, please do as follows. 1. Select the cells you will remove texts before or after a specific character, press Ctrl + H keys to open the Find and Replace dialog.

You are missing the .* (matching any number of chars) before the , (and a space after it which you probably also want to remove:

>>> new_s = re.sub('.*, ', '', '9 - Saturday, 19 May 2012')
>>> new_s
'19 May 2012'

How to remove all the characters on a line before a specified , In "Search and Replace" dialogue box (Press Ctrl + H ). Under "Search Mode", Choose "Regular Expression". Under "Find What: ", paste. ^.+[.]. Advertising Reach developers worldwide; Remove text from string until it reaches a certain character. So basically I want to remove everything till it reaches

Your regex is matching a single comma only hence that is the only thing it removes.

You may use a negated character class i.e. [^,]* to match everything until you match a comma and then match comma and trailing whitespace to remove it like this:

>>> print re.sub('[^,]*, *', '', '9 - Saturday, 19 May 2012')
19 May 2012

How can I delete rest of the line after a specific string?, For instance: rs<-c("copyright @ The Society of mo","I want you to meet me @ the coffeshop") s<-gsub("@.*","",rs) s [1] "copyright " "I want you to meet me ". Analyzing string input until it reaches a certain letter on Python random imputed string input be analyzed for a certain character and then get to remove the

Regex is great, but for this you could also use .split()

test_string = "9 - Saturday, 19 May 2012"
splt_string = test_string.split(",")
out_String = splt_string[1]



 19 May 2012

If the leading ' ' is a propblem, you can remedy this with out_String.lstrip()

removing strings after a certain character in a given text, =REGEXEXTRACT(B5, "[^\s|]+"). 0. \s a space; \s| a space followed by | character; ^ the first; ^\s| the first match of a space followed by | character; [] a group; [^\s|]  To get the last word from a text string, you can use a formula based on the TRIM, SUBSTITUTE, RIGHT, and REPT functions. In the example shown, the formula in C6 is: = TRIM ( RIGHT ( SUBSTITUTE ( B6 , " " , REPT ( " " , 100 )),

try this

a = "9 - Saturday, 19 May 2012"
f = a.find("19 May 2012")
b = a[f:]

Drop part of a cell value after a specific character, Removing characters before, after, and in the middle of strings character it was given and deletes that character..lstrip() #strips everything before and to '​Florence Briggs Thayer' because .rstrip() works like .lstrip() but at the end of the word. This will match any single character at the beginning of a string, except a, b, or c. If you add a * after it – /^[^abc]*/ – the regular expression will continue to add each subsequent character to the result, until it meets either an a, or b, or c.

Removing characters before, after, and in the middle of strings, Find the “position-minus-one” of the character. Subtract one from the other to determine how many characters to keep. Use that answer to keep the remaining​  If u need exactly after certain character, (say 20 words incl space). You can go for DATA tab, Then select the column you want changes then go to TEXT TO COLUMNS ribbon. After that a dialogue box will open and u can see Fixed width, Select it. Click next, then u will see 10, 20, 30, click on 20 (or how many words u need after), then next. FINISH.

In Google Sheets, how do we remove content before a certain , Trim or RegEx: How to remove string after special character in regex, just cant quite figure out how to start the parsing at the end of the word. Hi, For example, i have a string "123 456 789 abc 111 222 333" and I would like to delete all the characters before abc so that it becomes "abc 111 222 333" how can i do that in unix? using sed? note: I actually don't know how many words/charachters before "abc", so the "cut" command should not work.

Solved: Trim or RegEx: How to remove string after special , If I had a string like "1234///5678" and I wanted to remove everything after the first cannot understand special words like "int" or "func" or something like those, inventory item until I find any with that particular attribute, is there anyway to It's almost reached a point where I don't think I can handle the class much longer. This formula will extract the right-most 14 characters in a text string in Cell B1, so you can see that the text before the first comma character in a text string is removed. If you want to remove characters before the first occurrence of the space character or others specific characters,

  • new_s = re.sub('[^,]*, ', '', '9 - Saturday, 19 May 2012')
  • In the future, don't use snippets for languages other than html, js, or css, they do not run.
  • Will you ever have strings with more than 1 date that you need?
  • Split on comma and keep only the 2nd half? Why use regex?
  • Hi, I see you're new to SO. If you feel an answer solved the problem, please mark it as 'accepted’ by clicking the green check mark. This helps keep the focus on older SO which still don't have answers.
  • Shouldn't use string as a variable name, in some versions of python its the name of a builtin module.
  • I use string just for clarify the string is a string, not anything else