## How to manage division of huge numbers in Python?

I have a 100 digit number and I am trying to put all the digits of the number into a list, so that I can perform operations on them. To do this, I am using the following code:

for x in range (0, 1000): list[x] = number % 10 number = number / 10

But the problem I am facing is that I am getting an overflow error something like too large number float/integer. I even tried using following alternative

number = int (number / 10)

How can I divide this huge number with the result back in integer type, that is no floats?

In Python 3, `number / 10`

will try to return a `float`

. However, floating point values can't be of arbitrarily large size in Python and if `number`

is large an `OverflowError`

will be raised.

You can find the maximum that Python floating point values can take on your system using the `sys`

module:

>>> import sys >>> sys.float_info.max 1.7976931348623157e+308

To get around this limitation, instead use `//`

to get an integer back from the division of the two integers:

number // 10

This will return the `int`

floor value of `number / 10`

(it does not produce a float). Unlike floats, `int`

values can be as large as you need them to be in Python 3 (within memory limits).

You can now divide the large numbers. For instance, in Python 3:

>>> 2**3000 / 10 OverflowError: integer division result too large for a float >>> 2**3000 // 10 123023192216111717693155881327...

**How to manage division of huge numbers in Python?,** How can I divide this huge number with the result back in integer type, that is no floats? Solution. In Python 3, number / 10 will return try to return a float . However, You can divide large numbers in python as you would normally do. But this has a lot of precision issues as such operations cannot be guaranteed to be precise as it might slow down the language.

If you have an integer and you want each digit in a list, you can use:

>>> map(int,list(str(number))) [1, 5, 0, 3, 0, 0, 7, 6, 4, 2, 2, 6, 8, 3, 9, 7, 5, 0, 3, 6, 6, 4, 0, 5, 1, 2, 4, 3, 7, 8, 2, 5, 2, 4, 4, 5, 4, 8, 4, 0, 6, 6, 4, 5, 0, 9, 2, 4, 8, 9, 2, 9, 7, 8, 7, 3, 9, 9, 9, 7, 0, 1, 7, 4, 8, 2, 4, 4, 2, 9, 6, 9, 5, 1, 7, 1, 3, 4, 8, 5, 1, 3, 3, 1, 7, 9, 0, 1, 0, 1, 9, 3, 8, 4, 2, 0, 1, 9, 2, 9]

it transform the int into a string, then `list`

will take each character of the string and put it in a list. Finally, `map`

will convert each item of the list into an int again

**dividing large numbers,** using Decimal to divide large numbers by other large numbers would like Python can handle numbers as long as they fit into memory. Try to How to manage division of huge numbers in Python? (4) I have a 100 digit number and I am trying to put all the digits of the number into a list, so that I can perform operations on them. To do this, I am using the following code: for x in range (0, 1000): list [x] = number % 10 number = number / 10

Python will automatically handle large `int`

s of arbitrary length. What it won't do is handle `float`

s of arbitrary length so you need to make sure you're not getting floats along the way.

**Handling very large numbers in Python,** floating point How to manage division of huge numbers in Python? >>> 2**3000 / 10 OverflowError: integer division result too large for a float >>> 2**3000 // 10 Output: 2 -3 First output is fine, but the second one may be surprising if we are coming Java/C++ world. In Python 2.7, the “/” operator works as a floor division for integer arguments.

Try `int(number) % 10`

. You can only mod integers.

**How can python deal with bigger numbers than sys.maxint? : Python ,** What's Difference? Quizzes expand_more. C · C++ · Java · Python · Data Structures · Algorithms · Operating Systems · DBMS · Compiler Design Multiplying and dividing numbers in Python is really straightforward. If you've ever multiplied or divided numbers in other coding languages, you'll find the process for doing so in Python is really similar, if not pretty much exactly the same.

**Python Programming/Operators,** In Python 2.7, the “/” operator works as a floor division for integer arguments. However, the operator / returns a float value if one of the arguments is a float (this is Quite a few of the columns have HUGE values. The largest was 40 digits long! I used pd.read_csv but those columns have been converted to objects as a result. My original plan was to scale the data down but since they are seen as objects I can't do arithmetic on these. Does anyone have a suggestion on how to handle huge numbers in Pandas or Numpy?

**floating point How to manage division of huge numbers in Python ,** Large numbers are used in code challenges because they are hard to deal with, int' or 'long' on a typical x86 compiler, and vanilla configurations of python will Of course, using integer division the answer will be zero. How to compute huge numbers with python? Ask Question Asked 6 years, 1 month ago. Active 6 years, 1 month ago. Viewed 11k times 2. I'm currently trying to find the

**Divide large number represented as string,** You can divide large numbers in python as you would normally do. But this has a lot of precision issues as such operations cannot be In Python 3, / is float division. In Python 2, / is integer division (assuming int inputs) In both 2 and 3, // is integer division (To get float division in Python 2 requires either of the operands be a float, either as 20. or float(20))