## Remove all occurrences of a value from a list?

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In Python `remove()` will remove the first occurrence of value in a list.

How to remove all occurrences of a value from a list?

This is what I have in mind:

```>>> remove_values_from_list([1, 2, 3, 4, 2, 2, 3], 2)
[1, 3, 4, 3]
```

Functional approach:

2.x

```>>> x = [1,2,3,2,2,2,3,4]
>>> filter(lambda a: a != 2, x)
[1, 3, 3, 4]
```

3.x

```>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter((2).__ne__, x))
[1, 3, 3, 4]
```

or

```>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter(lambda a: a != 2, x))
[1, 3, 3, 4]
```

Python, Logic: Run a while loop from 0th element to last element's index. Check the element whether it is equal to the number (which is to be removed) or not. If any element of the list is equal to the number (which is to be removed), remove that element from the list. To remove the number from the list, use list. In the test above we always call list.remove(1), but the element's index we want to remove is 0. Calling List.remove() shifts all elements after the removed one to smaller indices. In this scenario, it means that we delete all elements, except the first. When only the first remains, the index 1 will be illegal. Hence we get an Exception.

You can use a list comprehension:

```def remove_values_from_list(the_list, val):
return [value for value in the_list if value != val]

x = [1, 2, 3, 4, 2, 2, 3]
x = remove_values_from_list(x, 2)
print x
# [1, 3, 4, 3]
```

Remove all instances of a value from a list, Is there a way to remove all instances of a value in a list? For example, if I have: my_list = [1, 2, 3, 3, 3]. my_list.remove(3) results in my_list = [1,  Ask the user to enter the number to remove from the list. Store it in the flag variable. Run a while loop and check continuously if the flag exists in the user_list or not. If yes, remove it from the list. The remove() method removes the first occurrence of a value from a list. So, we need to call it multiple times if that number has multiple occurrences in that list.

You can use slice assignment if the original list must be modified, while still using an efficient list comprehension (or generator expression).

```>>> x = [1, 2, 3, 4, 2, 2, 3]
>>> x[:] = (value for value in x if value != 2)
>>> x
[1, 3, 4, 3]
```

Remove All Occurrences of a Specific Value from a List, In this tutorial, we'll see multiple solutions to efficiently removing all occurrences of a value, describing the pros and cons. Remove all instances of a value from a list Is there a way to remove all instances of a value in a list? For example, if I have: my_list = [1, 2, 3, 3, 3] my_list.remove(3) results in my_list = [1, 2, 3, 3].

Repeating the solution of the first post in a more abstract way:

```>>> x = [1, 2, 3, 4, 2, 2, 3]
>>> while 2 in x: x.remove(2)
>>> x
[1, 3, 4, 3]
```

Python, Sometimes we need to perform the operation of removing all the items from the lists that are present in other list, i.e we are given some of the invalid numbers in​  There are two ways to remove all the Items with a specific value from the List. Iterate through the items of list and use remove() method when the item’s value matches the item of our interest. Filter the List with lambda function having a condition that the item should be not the item of our interest.

See the simple solutions Solution 1:

```>>> [i for i in x if i != 2]
```

This will return a list having all elements of `x` without `2` Solution 2:

```>>> while 2 in x : x.remove(2)
```

Remove all occurrences of a value from a list, in Haskell, Remove all occurrences of value x from list items. This will alter the original list or return a new list, depending on which is more idiomatic. Haskell  I would like to implement a program in python where all occurrences of a value are removed from a list in place and in linear time (O(n)). There have been posts of problems similar to this, but none had the constraint of doing it in linear time.

Python Remove all Occurrences of an Item from List, There are two ways to remove all the Items with a specific value from the List. Iterate through the items of list and use remove() method when the item's value  If any element of the list is equal to the number (which is to be removed), remove that element from the list. To remove the number from the list, use list.remove() method . After removing the number/element from the list, decrease the length, because one item is deleted, and then continue the loop to check the next item at same index (because after removing the element – next elements shifts to the previous index.

ArrayList removeAll(), It removes all occurrences of matching elements, not only first occurrence. 1. ArrayList removeAll() method. Internally, the removeAll() method iterate over all  Delete all occurrences of a given key in a linked list. Given a singly linked list, delete all occurrences of a given key in it. For example, consider the following list. Input: 2 -> 2 -> 1 -> 8 -> 2 -> 3 -> 2 -> 7 Key to delete = 2 Output: 1 -> 8 -> 3 -> 7. This is mainly an extension of this post which deletes first occurrence of a given key.

[Python-ideas] Proposal how to remove all occurrences of a value , the main idea of this proposal is to create convenient, maybe more >> Pythonic way to remove all occurrences of a value from a Python list. Remove all occurrences of an element from Array in Java Which Java libraries are useful for competitive programming? Integer.MAX_VALUE and Integer.MIN_VALUE in Java with Examples